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pH calculations for weak acids, Lecture notes of Chemistry

We make two assumptions to calculate the pH of a weak acid. [HA] For example: Find the pH of a 1.50 mol. L-1 solution of HOBr. (HOBr) = 2.40 x 10-9.

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pH calculations for weak acids
How can we calculate the pH of a weak acid? How do we know
[H3O+] if the solution has not fully dissociated?
We use a new constant!! Ka
HA + H2O H3O++ A-Ka= [H3O+] [A-]
[HA]
The higher the Kathe stronger the acid.
pKa= -log10KaKa= 10-pKa
Workbook pg 221 223
The lower the pKathe stronger the acid.
pf3
pf4
pf5
pf8
pf9
pfa

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pH calculations for weak acids

How can we calculate the pH of a weak acid? How do we know [H 3 O

] if the solution has not fully dissociated? We use a new constant!! K a HA + H 2

O H

3

O

  • A
  • K a

= [H

3

O

] [A

  • ] [HA] The higher the Ka the stronger the acid. pK a = - log 10

K

a

K

a

  • pKa Workbook pg 221 – 223 The lower the pKa the stronger the acid.

2014 Exam Q1 b

pH calculations for weak acids

Find the pH of 0.0500 mol.L

  • 1 HF. K a (HF) = 7.2 x 10 - 4 Find the pH of 0.750 mol.L
  • 1 CH 3 COOH. pK a

(CH

3

COOH) = 4.

Workbook pg 231 The pH of a solution of acetic acid is 3.42. What is the concentration of the acid solution? K a

(CH

3 COOH) = 1.78 x 10

  • 5

2013 Exam Q

Sometimes part of a bigger question on buffers/titrations (last topics)

pH calculations for weak bases

For example: Find the pH of a 0.53 mol.L

  • 1 solution of sodium ethanoate (NaCH 3

COO).

Ka(CH 3 COOH) = 1.74 x 10

CH 3

COO

    • H 2

O CH

3

COOH + OH

NaCH 3 COO  Na

  • CH 3 COO

Kb = [OH

] 2 [CH 3

COO

  • ] 5.75 x 10
  • 10 = [OH

] 2

[OH

] = 5. 75 × 10 − 10 × 0. 53 [OH

] = 1.75 x 10

  • 5 pOH = - log 10 (1.75 x 10
  • 5 ) pOH = 4.

K

b

= K

w

  • 14 K b = 5.75 x 10
  • 10 pH = 9. Ka 1.74 x 10
  • 5 pH = 14 - pOH Workbook pg 232 Workbook pg 234 – 235 if finished

2012 Exam Q3 a

2011 Exam Q 1 c

2014 Exam Q 3 b