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ae Was yee 5 Wednesday, December 8, 2010 i. neu. Whe low ¢ oe.” (Final exam version “B”) ~ 2010 - Physics 33 Final Exam “B” Do all problems. Show all work. Basic calculator allowed. General formula sheet piovided. No other references allowed. Good luck!!! name: (1) A conducting bar of length D = 20 cm rotates with angular frequency w = 0.2 rad/sec about a pivot “P” at one end of the bar. The other end of the bar is in slipping contact with a stationary conducting wire in the shape of a circular arc (see figure below). Between point “P” and the circular wire there is a resistor R = 10 Q as shown. Thus the bar, the resistor and the wire form a closed loop. Assume all of the circuit resistance is contained in the value of R. A uniform magnetic field B = 1.5 Tesla points “into the sf page” everywhere. (a) In which direction is the current induced in the loop? (b) Compute the induced EMF (voltage). Hint: The area within a circular arc defined by radius ‘r’ and A@ is sa’(A@/2z). 6 ewe B DB caveedt Wndiad te counsecect a ae OS c induad to utnk OF eis eee), “fe @ eme= cid, $6 .aA = © d(&) \c mF |=e¢, [atrl | cas (180° on = @ filre) Nip tepashend *@ d (reg)~ 64( 58) pa » #2) go lene = Mustebbizeal (29) 7 Gil 2) A 3 uF capacitor and a 5 uF capacitor are connected in series. A 10 volt battery is connected across the combination. After the capacitors are fully charged, what is the voltage across the 5yF capacitor? = loV cap uF Qzsame oh Q x Qs \ov = Qt me Ti gee ote ’ Qx 1ov C8 PE) = LB Bx10 God F (3) = | eexd cow) Vaiten = 4° le sf ; a L. 84x10 Col J LAN Vex 3.46 Vets PS Nap Se ) 
