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Point Estimate and Confidence Intervals for Population Proportion and Mean, Study notes of Mathematical Statistics

Formulas and examples for calculating point estimates, margins of error, and confidence intervals for population proportions and means. It includes formulas for z-table, t-table, chi-square table, and degrees of freedom. A survey example is given to illustrate the concepts.

What you will learn

  • What is the formula for calculating the point estimate for a population proportion?
  • What is the difference between using a z-table and a t-table for confidence intervals?
  • How do you find the margin of error for a population mean?

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Point Estimate
๐‘๎žธ=๐‘ฅ
๐‘› ๐‘๎žธ is the point estimate for the population proportion, ๐‘ฅ is the number of
successes, n is the sample size
๐‘๎žธ=๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘+๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘
2 for the population proportion
๐‘ฅ๎ชง=๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘+๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘
2 for the population mean
๐ธ=๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘โˆ’๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘
2 -> ๐ธ is the margin of error (can be used for either)
A survey was given to 1500 students in a school to find the proportion of students who
are interested in taking a musical course. Determine the point estimate, margin of error,
and number of students who responded they would be interested in a musical course,
based on the given upper and lower bounds.
Lower bound = .682 Upper bound = .746
๐‘๎žธ=๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘ + ๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘
2=.746+.682
2=.714
๐ธ=๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘ โˆ’ ๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘
2=.746โˆ’.682
2=0.032
๐‘๎žธ=๐‘ฅ
๐‘› -> ๐‘ฅ=๐‘๎žธโˆ™๐‘›=.714โˆ™1500=1071 ๐‘ ๐‘ก๐‘ข๐‘‘๐‘’๐‘›๐‘ก๐‘  ๐‘–๐‘›๐‘ก๐‘’๐‘Ÿ๐‘’๐‘ ๐‘ก๐‘’๐‘‘
Confidence Intervals
Population proportion: ๐‘๎žธยฑ๐‘ง๐‘Ž 2
โ„โˆ™โˆš๐‘๏œ(1โˆ’๐‘
๏œ)
๐‘› -> Use z-table
Population mean: ๐‘ฅ๎ชงยฑ๐‘ก๐‘Ž 2
โ„โˆ™๐‘ 
โˆš๐‘› -> Use t-table
Population variance: (๐‘›โˆ’1)๐‘ 2
๐œ’๐‘Ž 2
โ„
2,(๐‘›โˆ’1)๐‘ 2
๐œ’1โˆ’๐‘Ž 2
โ„
2 -> Use chi-square table
Population standard deviation: โˆš(๐‘›โˆ’1)๐‘ 2
๐œ’๐‘Ž 2
โ„
2,โˆš(๐‘›โˆ’1)๐‘ 2
๐œ’1โˆ’๐‘Ž 2
โ„
2 -> Use chi-square table
๐‘Ž
2=1 โˆ’ ๐ถ๐‘œ๐‘›๐‘“๐‘–๐‘‘๐‘’๐‘›๐‘๐‘’ ๐ฟ๐‘’๐‘ฃ๐‘’๐‘™
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Point Estimate

๐‘ฬ‚ = (^) ๐‘›๐‘ฅ ๐‘ฬ‚ is the point estimate for the population proportion, ๐‘ฅ is the number of

successes, n is the sample size

๐‘ฬ‚ = ๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘+๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘ 2 for the population proportion

๐‘ฅฬ… = ๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘+๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘ 2 for the population mean

๐ธ = ๐‘ˆ๐‘๐‘๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘โˆ’๐ฟ๐‘œ๐‘ค๐‘’๐‘Ÿ ๐ต๐‘œ๐‘ข๐‘›๐‘‘ 2 -> ๐ธ is the margin of error (can be used for either)

A survey was given to 1500 students in a school to find the proportion of students who are interested in taking a musical course. Determine the point estimate, margin of error, and number of students who responded they would be interested in a musical course, based on the given upper and lower bounds.

Lower bound = .682 Upper bound =.

Confidence Intervals

Population proportion: ๐‘ฬ‚ ยฑ ๐‘ง๐‘Ž 2โ„ โˆ™ โˆš๐‘ฬ‚(1โˆ’๐‘ฬ‚)๐‘› -> Use z-table

Population mean: ๐‘ฅฬ… ยฑ ๐‘ก๐‘Ž 2โ„ โˆ™ (^) โˆš๐‘›๐‘  -> Use t-table

Population variance: (๐‘›โˆ’1)๐‘ 

2 ๐œ’๐‘Ž 2^2 โ„^ ,^

(๐‘›โˆ’1)๐‘ ^2 ๐œ’1โˆ’๐‘Ž 2^2 โ„ ->^ Use chi-square table

Population standard deviation: (^) โˆš

(๐‘›โˆ’1)๐‘ ^2 ๐œ’๐‘Ž 2^2 โ„^ , โˆš

(๐‘›โˆ’1)๐‘ ^2 ๐œ’1โˆ’๐‘Ž 2^2 โ„ ->^ Use chi-square table

Common critical values for the POPULATION PROPORTION ONLY:

For the population mean, variance, or standard deviation, the degrees of freedom (df), will also be needed to find the critical value.

๐‘‘๐‘“ = ๐‘› โˆ’ 1

Sample Size

Always round up to the next integer

Population proportion: ๐‘› = ๐‘ฬ‚(1 โˆ’ ๐‘ฬ‚)(๐‘ง๐‘Ž 2 ๐ธโ„ )^2

**If there are no prior estimates, then use ๐‘ฬ‚ =.

Population mean: ๐‘› = (

๐‘ง๐‘Ž 2โ„ โˆ™๐‘ 

2

Examples: A survey of 500 airline passengers found that 338 were satisfied with the service they received from the flight attendants. Calculate and interpret a 95% confidence interval for the proportion of passengers who are satisfied with the service from flight attendants.

๏‚ท Because we are looking for a population proportion, first we need to find the point estimate, and then we will use the z-table in our confidence interval for the critical value.

๐‘ฬ‚ =

Now, we use ๐‘ฬ‚ ยฑ ๐‘ง๐‘Ž 2โ„ โˆ™ โˆš๐‘ฬ‚(1โˆ’๐‘ฬ‚)๐‘› , and use the z-table. For a 95% confidence interval, the

critical value is 1.

Confidence Level

Critical Value (Z-Score) 90% 1. 95% 1. 98% 2. 99% 2.

A survey given to 25 incoming freshmen at a college in Illinois has shown that the average composite ACT score of an incoming freshman is 21.4. The standard deviation of these ACT scores for those freshmen is 5.78. Calculate and interpret a 90% confidence interval for the population standard deviation of composite ACT scores at that college in Illinois.

๏‚ท Because we are estimating the population standard deviation, we will use the chi- square table. For the confidence interval, we will use (^) โˆš(๐‘›โˆ’1)๐‘ 

2 ๐œ’๐‘Ž 2^2 โ„^ , โˆš

(๐‘›โˆ’1)๐‘ ^2 ๐œ’1โˆ’๐‘Ž 2^2 โ„

๐‘Ž 2 =^

1โˆ’. 2 = .05,^ 1 โˆ’^

๐‘Ž 2 = 1 โˆ’ .05 =.

The degrees of freedom is 25-1, or 24. The two critical values then come from df=24, ๐‘Ž/2 = .05, and df=24, ๐‘Ž = .95. Those critical values are 36.415 and 13.

(25 โˆ’ 1)5.78^2

(25 โˆ’ 1)5.78^2

Our 90% confidence interval is thusly (4.69, 7.61)

We are 90% confident that the population standard deviation of composite ACT scores at the college in Illinois is between 4.69 and 7.61.

Using the ACT data, compute and interpret a 99% confidence interval for the mean composite ACT score at the college in Illinois.

๏‚ท Because we are estimating the population mean, we will need to use the t-table. The degrees of freedom is still 24. Now we will find ๐›ผ/2.

๐‘Ž 2 =^

1โˆ’. 2 =.

With df=24, and ๐‘Ž = .005, we look at the t-table, and get a critical value of 2.

Now we use ๐‘ฅฬ… ยฑ ๐‘ก๐‘Ž 2โ„ โˆ™ (^) โˆš๐‘›๐‘ 

The 99% confidence for the mean composite ACT score is (18.167, 24.633)

We are 99% confident that the population mean composite ACT score at the college in Illinois is between 18.167 and 24.

A political firm wants to conduct a survey to gauge voter interest of a particular candidate in the state of Minnesota. They are looking for a 95% confidence level, and the margin of error desired on the survey is 2%. What is the sample size needed if the prior estimate of people in favor of this candidate is 41%?

๏‚ท Because we are working with population proportion, we will use ๐‘› = ๐‘ฬ‚(1 โˆ’ ๐‘ฬ‚)(๐‘ง๐‘Ž 2 ๐ธโ„ )^2 ๏‚ท Also, ๐‘ง๐‘Ž 2โ„ = 1.96 for 95% confidence

2 = 2323.

So the political firm would need 2324 participants in the survey

What if there were no prior estimates?

๏‚ท Without prior estimates, we use ๐‘ฬ‚ =.

๐‘› = .5(1 โˆ’ .5) (1.96.02 )

2 = 2401

With no prior estimates, the political firm would need 2401 participants for the survey