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Polynomial Functions In Factored Form, Schemes and Mind Maps of Algebra

A more useful way to write a polynomial function's equation is to use factored form, such as f (x)=(x - 1)(x + 2)(x + 3). Each factor corresponds to an x- ...

Typology: Schemes and Mind Maps

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polynomial functions
MHF4U: Advanced Functions
Equations and Graphs of Polynomial Functions
J. Garvin
Slide 1/18
polynomial functions
Polynomial Functions In Factored Form
Polynomials are generally written in standard form, such as
f(x) = x3+ 4x2+x6.
A more useful way to write a polynomial function’s equation
is to use factored form, such as f(x)=(x1)(x+ 2)(x+ 3).
Each factor corresponds to an x-intercept of the function.
Factored Form of a Polynomial Function
An equation of a polynomial function is in factored form if it
is written as f(x) = a(xr1)(xr2). . . (xrn), where
(xrk) is a factor corresponding to x-intercept rk.
Note that it is not always possible to express a polynomial
function using factored form.
J. Garvin Equations and Graphs of Polynomial Functions
Slide 2/18
polynomial functions
Polynomial Functions In Factored Form
Example
Identify the factors, and x-intercepts, of the polynomial
function f(x) = 2x(x+ 5)(x3).
f(x) has three factors: x,x+ 5 and x3.
These factors correspond to x-intercepts 0, 5 and 3.
J. Garvin Equations and Graphs of Polynomial Functions
Slide 3/18
polynomial functions
Order of a Factor
Examine the x-intercepts of f(x)=6x(x1)2(x2)3below.
How does the function behave around each x-intercept?
J. Garvin Equations and Graphs of Polynomial Functions
Slide 4/18
polynomial functions
Order of a Factor
The function f(x) = 6x(x1)2(x2)3has x-intercepts at
0, 1 and 2.
At x= 0, the function changes from positive to negative,
passing through the x-axis.
The function remains negative on either side of x= 1,
“bouncing” off of the x-axis.
At x= 2, the function changes from negative to positive,
passing through the x-axis.
How does this behaviour relate to the factors of the function?
J. Garvin Equations and Graphs of Polynomial Functions
Slide 5/18
polynomial functions
Order of a Factor
In two cases, x= 0 and x= 2, the exponents were odd.
Both of these cases saw the function change from positive to
negative, or vice versa.
In the other case, x= 1, the exponent was even. No change
in sign occurred here.
Order of a Factor
The factor (xr)nhas order n. If nis odd, the function
crosses the x-axis at r. If nis even, the function touches (but
does not cross) the x-axis at r.
Used in conjunction with a function’s end behaviour,
identifying the order of each factor is a useful tool for
sketching graphs.
J. Garvin Equations and Graphs of Polynomial Functions
Slide 6/18
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MHF4U: Advanced Functions

Equations and Graphs of Polynomial Functions

J. Garvin

Slide 1/

Polynomial Functions In Factored Form

Polynomials are generally written in standard form, such as f (x) = x^3 + 4x^2 + x − 6. A more useful way to write a polynomial function’s equation is to use factored form, such as f (x) = (x − 1)(x + 2)(x + 3). Each factor corresponds to an x-intercept of the function. Factored Form of a Polynomial Function An equation of a polynomial function is in factored form if it is written as f (x) = a(x − r 1 )(x − r 2 )... (x − rn), where (x − rk ) is a factor corresponding to x-intercept rk.

Note that it is not always possible to express a polynomial function using factored form.

J. Garvin — Equations and Graphs of Polynomial FunctionsSlide 2/

p o l y n o m i a l f u n c t i o n s

Polynomial Functions In Factored Form

Example Identify the factors, and x-intercepts, of the polynomial function f (x) = − 2 x(x + 5)(x − 3).

f (x) has three factors: x, x + 5 and x − 3.

These factors correspond to x-intercepts 0, −5 and 3.

J. Garvin — Equations and Graphs of Polynomial Functions Slide 3/

p o l y n o m i a l f u n c t i o n s

Order of a Factor

Examine the x-intercepts of f (x) = 6x(x − 1)^2 (x − 2)^3 below.

How does the function behave around each x-intercept?

J. Garvin — Equations and Graphs of Polynomial Functions Slide 4/

p o l y n o m i a l f u n c t i o n s

Order of a Factor

The function f (x) = 6x(x − 1)^2 (x − 2)^3 has x-intercepts at 0, 1 and 2.

At x = 0, the function changes from positive to negative, passing through the x-axis.

The function remains negative on either side of x = 1, “bouncing” off of the x-axis.

At x = 2, the function changes from negative to positive, passing through the x-axis.

How does this behaviour relate to the factors of the function?

p o l y n o m i a l f u n c t i o n s

Order of a Factor

In two cases, x = 0 and x = 2, the exponents were odd. Both of these cases saw the function change from positive to negative, or vice versa. In the other case, x = 1, the exponent was even. No change in sign occurred here. Order of a Factor The factor (x − r )n^ has order n. If n is odd, the function crosses the x-axis at r. If n is even, the function touches (but does not cross) the x-axis at r.

Used in conjunction with a function’s end behaviour, identifying the order of each factor is a useful tool for sketching graphs.

Graphs of Polynomial Functions

Example

Sketch a graph of f (x) = (x + 3)^2 (x − 1).

f (x) has two distinct x-intercepts, at x = −3 and x = 1.

Another way to write the equation is f (x) = (x + 3)(x + 3)(x − 1). Multiplying all terms containing x, we obtain x^3 , so f (x) has degree 3 (cubic).

The leading coefficient is positive, so f (x) has Q3-Q1 end behaviour. Therefore, f (x) is negative as x → −∞.

Moving from left to right, the first x-intercept is at x = −3, where it has order 2. Thus, the function touches the x-axis at x = −3, but stays negative beyond it.

The next x-intercept is at x = 1, where it has order 1. f (x) changes from negative to positive at x = 1. J. Garvin — Equations and Graphs of Polynomial FunctionsSlide 7/

Order of a Factor

One final piece point is the y -intercept, which can be found by multiplying all of the constant terms and the leading coefficient. In this case, the y -intercept is (3)(3)(−1) = −9.

J. Garvin — Equations and Graphs of Polynomial FunctionsSlide 8/

p o l y n o m i a l f u n c t i o n s

Graphs of Polynomial Functions

Example

Sketch a graph of f (x) = − 2 x(x + 1)(x − 2)^2.

f (x) has three distinct x-intercepts, at x = −1, x = 0 and x = 2.

f (x) is a quartic function, with degree 4.

The leading coefficient is negative, so f (x) has Q3-Q4 end behaviour. f (x) is negative as x → −∞.

From left to right, f (x) changes from negative to positive at x = −1, changes from positive to negative at x = 0, and touches the x-axis at x = 2.

The y -intercept is −2(0)(1)(−2)(−2) = 0.

J. Garvin — Equations and Graphs of Polynomial Functions Slide 9/

p o l y n o m i a l f u n c t i o n s

Graphs of Polynomial Functions

J. Garvin — Equations and Graphs of Polynomial Functions Slide 10/

p o l y n o m i a l f u n c t i o n s

Graphs of Polynomial Functions

Example Given the graph of f (x) below, state the minimum possible degree, sign of the leading coefficient, factors, x-intercepts and intervals where the function is positive or negative.

p o l y n o m i a l f u n c t i o n s

Graphs of Polynomial Functions

f (x) has Q2-Q4 end behaviour, so the degree must be odd and the leading coefficient is negative. There are x-intercepts at x = −3 (even order), x = 0 (odd order) and x = 2 (even order), so the minimum degree is 5. This is confirmed by the fact that there are 4 local minimums and maximums. f (x) is positive on the intervals (−∞, −3) ∪ (− 3 , 0). Since zero is neither positive nor negative, it is not included in the interval. f (x) is negative on the intervals (0, 2) ∪ (2, ∞).