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Practice Exam 1 for Real Analysis I | MATH 323, Exams of Mathematical Methods for Numerical Analysis and Optimization

Material Type: Exam; Class: Real Analysis I; Subject: Mathematics; University: Colgate University; Term: Fall 2001;

Typology: Exams

Pre 2010

Uploaded on 08/18/2009

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September 24, 2001
Math 323 Practice Exam I
1. (25 points) Using the definition of limit (i.e., not the Algebraic Limit Theorem), prove the
following:
(a) lim(n/n2+ 1) = 1.
(b) If lim xn=xand lim yn=y, then lim(xn+ 2yn) = x+ 2y.
2. (20 points) In class, we proved (in an unnecessarily complicated way) that, if anbnfor all
nNand lim an=aand lim bn=b, then ab.
(a) Show by example that we cannot replace with >throughout the statement.
(b) Prove on the basis of the result above that, if anBfor all nN(where Bis a real
constant), then lim anB.
3. (20 points) Consider the function
f(x) =
1 if x< 0,
0 if x= 0 ,
1 if x> 0.
For a set Afor which inf A= 0, is it true that inf{f(a) : aA}=f(inf A)? What can
we say about sets which also have infima, but the infima are different from 0? What is the
corresponding statement for suprema?
4. (10 points) Archimedes proposed finding the circumference of a circle as follows: “Inscribe in
the circle an equilateral triangle, then double the number of sides to form a regular hexagon,
then again to form a regular 12-sided figure (a dodecagon), and so on. The perimeters of
these polygons get close to the circumference of the circle.” Put aside the question of whether
this process gives the correct answer. What do we need to show to be sure that it gives any
answer at all? And how might we show it?
pf3
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September 24, 2001 Math 323 — Practice Exam I

  1. (25 points) Using the definition of limit (i.e., not the Algebraic Limit Theorem), prove the following: (a) lim(n/

n^2 + 1) = 1. (b) If lim xn = x and lim yn = y, then lim(xn + 2yn) = x + 2y.

  1. (20 points) In class, we proved (in an unnecessarily complicated way) that, if an ≥ bn for all n ∈ N and lim an = a∗^ and lim bn = b∗, then a∗^ ≥ b∗. (a) Show by example that we cannot replace ≥ with > throughout the statement. (b) Prove on the basis of the result above that, if an ≥ B for all n ∈ N (where B is a real constant), then lim an ≥ B.
  2. (20 points) Consider the function

f (x) =

  

−1 if x< 0 , 0 if x= 0 , 1 if x> 0. For a set A for which inf A = 0, is it true that inf{f (a) : a ∈ A} = f (inf A)? What can we say about sets which also have infima, but the infima are different from 0? What is the corresponding statement for suprema?

  1. (10 points) Archimedes proposed finding the circumference of a circle as follows: “Inscribe in the circle an equilateral triangle, then double the number of sides to form a regular hexagon, then again to form a regular 12-sided figure (a dodecagon), and so on. The perimeters of these polygons get close to the circumference of the circle.” Put aside the question of whether this process gives the correct answer. What do we need to show to be sure that it gives any answer at all? And how might we show it?
  1. (25 points) True or false? If true, prove it. If false, give a counterexample. (I will not say, as was suggested at the Columbus conference, “If false, give a counterexample, change it to a statement that is true and interesting, and prove that.”)

(a) If (an) and (bn) are bounded sequences in R, then (an + bn) is also bounded. (b) If xn ≤ yn ≤ zn for all n in N, and if lim xn = x and lim zn = z, then x ≤ lim yn ≤ z. (c) If sup A = a∗, then for all a in A and a < x < a∗, we have x ∈ A. (d) For any two real numbers a < b, there exists an irrational number c for which a < c < b.

(c) False. (This is a confusion that I’ve heard as some students describe suprema or limits.) A counterexample would be A = { 1 − (1/n) : n ∈ N} (with sup A = 1), a = 1 − (1/2) = 1 /2 and x = 5/8.

(d) True: Let d be any positive irrational number, and take a nonzero rational number q between a/d and b/d (which exists by the density of Q in R — if the first choice of a rational number between a/d and b/d is 0, then replace it with a rational number between 0 and b/d). Then c = qd is an irrational number between a and b.