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Practice Quiz 1 with Solutions for College Algebra and Trigonometry |, Quizzes of Trigonometry

Material Type: Quiz; Class: College Algebra and Trigonometry; Subject: Mathematics; University: National American University-Rapid City; Term: Forever 1989;

Typology: Quizzes

2010/2011

Uploaded on 05/04/2011

lawlessv21
lawlessv21 🇺🇸

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Question 1
Simplify (all exponents should be positive):
4x3 * (3y)4
= 4x^3 * 81y^4
= 324x^3y^4
Question 2
Simplify (all exponents should be positive):
(2^3a^-6b^-3)/(4a^-9)
= 2a^3 / b^3
Question 3
Simplify (all exponents should be positive):
(3x + 4y3 - 5y) - (2x + 3y3 - 5y)
3x + 4y^3 – 4y – 2x – 3y^3 + 5y
= x + y^3 + y
Question 4
Simplify (all exponents should be positive):
(4x3 + 2y) (2x3 - 3y)
FOIL:
8x^6 – 12x^3y + 4x^3y – 6y^2
= 8x^6 – 8x^3y – 6y^2
pf3
pf4
pf5

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Question 1

Simplify (all exponents should be positive):

4x^3 * (3y)^4

= 4x^3 * 81y^ = 324x^3y^ Question 2

Simplify (all exponents should be positive):

(2^3a^-6b^-3)/(4a^-9) = 2a^3 / b^ Question 3

Simplify (all exponents should be positive):

(3x + 4y^3 - 5y) - (2x + 3y^3 - 5y)

3x + 4y^3 – 4y – 2x – 3y^3 + 5y = x + y^3 + y Question 4

Simplify (all exponents should be positive):

(4x^3 + 2y) (2x^3 - 3y)

FOIL:

8x^6 – 12x^3y + 4x^3y – 6y^ = 8x^6 – 8x^3y – 6y^

Question 5

Simplify (all exponents should be positive):

(x + 4)^2

Use the square rule: x^2 + 8x + 16 Question 6

Simplify (all exponents should be positive):

(x + 5y) (x - 5y)

Difference of squares: x^2 – 25y^ Question 7

Write the result in scientific notation:

(3.86 x 10^15 ) * (2.15 x 10-7)

3.862.15 * 10^1510^-

= 8.299 * 10^

Question 8

Write the result in scientific notation:

(3.86 x 10^15 ) / (4.15 x 10-7)

3.864.15 * 10^1510^-

= 16.019 * 10^

= 1.6019 * 10^

Sum of cubes:

A^3 + B^3 factors to ( a + b )( a^2 - ab + b^2 )

a = y, b = 5 (y+5)(y^2-5y+25) Question 13

Solve:

x^3 = 4x

Subtract 4x: X^3 – 4x = 0 Factor: X(x^2 – 4) = 0 Factor the difference of squares: X(x-2)(x+2) = 0 So: X = 0, 2, or - Question 14

Solve:

4m^2 + 14m - 30 = 0

Divide by 2: 2m^2 + 7m – 15 = 0 Factor: (2m-3)(m+5) = 0 2m-3=0 or m+5= M = 3/2 or - Question 15

Solve:

| x^2 + 2x - 36 | = 12

Make two equations: X^2 + 2x – 36 = 12 and –x^2-2x+36= Subtract 12 from each: X^2 + 2x – 48 = 0 and –x^2 – 2x + 24 = 0

Factor each: (x+8)(x-6) = 0 and (x+6)(x-4) = 0 So x = -8, -6, 4, or 6 Question 16

Solve:

The bottom of Jim's rectangular bait box is 3 inches longer than it is wide. The

diagonal is 15 inches. What is the area of the bottom of the box?

area = lw L = w + 3 Pythagorean: A^2 + b^2 = c^ W^2 + (w+3)^2 = 15^ W^2 + w^2 + 6w + 9 = 225 Combine: 2w^2 + 6w – 216 = 0 Divide by 2: W^2 + 3w – 108 = 0 Factor: (w-9)(w+12) = 0 W = 9 or - The dimensions are 9 by 12. The area is 9 times 12: 108 square inches Question 17

Solve:

The greenhouse heats up in the sun according to the following formula: T = 55 + 2.

x 10-2^ * h^3 where h is the number of hours the sun hits the building. In December the

average number of hours that the sun will hit the greenhouse is 6.72. How warm

should we expect the greenhouse to get the end of an average day in December?

Plug in h = 6.72:

T = 55 + 2.356 x 10-2^ * h^3

T = 55 + 2.356 * 10^-2 * 6.72^

T = 62.