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Process Calculations Lecture notes in Chemical engineering, Lecture notes of Process Control

Process Calculations Lecture notes in Chemical engineering

Typology: Lecture notes

2021/2022

Available from 08/30/2023

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Exercise:
3. The natural gas at 298K having the following molar composition: CH4: 89.4%,
C2H6: 5%, C3H8: 1.9%, n-C4H10: 1%, CO2: 0.7%, N2: 2%. Data:
Compt GCV,
kJ/mol
NCV,
kJ/mol
CH4890.65 802.62
C2H61560.69 1428.64
C3H82219.17 2043.11
C4H10 2877.40 2657.32
Specific volume of at 298K and
101.325 kPa = 24.465 m3/kmol.
Calculate the GCV and NCV of the
natural gas in kJ/kmol, kJ/kg and
kJ/m3
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Exercise:

  1. The natural gas at 298K having the following molar composition: CH 4 : 89.4%, C 2 H 6 : 5%, C 3 H 8 : 1.9%, n-C 4 H 10 : 1%, CO 2 : 0.7%, N 2 : 2%. Data: Compt GCV, kJ/mol

NCV,

kJ/mol CH 4 890.65 802. C 2 H 6 1560.69 1428. C 3 H 8 2219.17 2043. C 4 H 10 2877.40 2657. Specific volume of at 298K and 101.325 kPa = 24.465 m 3 /kmol. Calculate the GCV and NCV of the natural gas in kJ/kmol, kJ/kg and kJ/m 3

Contd….

  1. The natural gas at 298K having the following molar composition: CH 4 : 89.4%, C 2 H 6 : 5%, C 3 H 8 : 1.9%, n-C 4 H 10 : 1%, CO 2 : 0.7%, N 2 : 2%. Data: Compt GCV, kJ/mol

NCV,

kJ/mol CH 4 890.65 802. C 2 H 6 1560.69 1428. C 3 H 8 2219.17 2043. C 4 H 10 2877.40 2657. Specific volume of at 298K and 101.325 kPa = 24.465 m 3 /kmol. Calculate the GCV and NCV of the natural gas in kJ/kmol, kJ/kg and kJ/m 3

  1. Pure propane (C 3 H 8 ) is burnt with an excess air to give the following combustion product in volume% CO 2 : 5, CO : 3.5, H 2 O : 11.4, O 2 : 7 and N 2 : 73.1. Calculate the % excess air used.
  1. 100 kg of pure S is burnt in a furnace with 65% excess air. During combustion, 90% of S is burnt to SO 2 and rest to SO 3. Estimate the composition of gases leaving.