Projectile Motion Lab Answers, Lab Reports of Physics

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Physics: Projectile Motion (Intro) PhET Simulations Lab Name: KEY Per. Introduction: a Projectiles travel with two components of motion, X any Y. The acceleration and velocity in the Y direction is independent of the acceleration (if any) and velocity in the X direction. In this:module, you will investigate the motion of a simple projectile: Realize that while gravity (acceleration) acts on the projectile in the verttea\ direction, it does not affect the velocity of the projectile in the _\ovizwwtal direction. Projectile Motion Procedure: e — Run the PhET Simulation (https://phet.colorado.edu/en/simulation/legacy/projectile-motion) ¢ The cannon can be moved to add or remove initial Y position and X position. e The cannon can be pivoted to change the firing angle, 9. e The tape measure can be moved and dragged to measure range to target. © To fire the cannon, (Fig), e Toerase the projectile’s path, Eng, Be sure air resistance is off and spend some time firing various projectiles. ° Set the initial speed to a value between 10-15 m/s. Choose your favorite projectile. e Find the range of the projectile at various angles. 6 = 30°: Range (Ax) =_]2.7 @ = 70°: Range (Ax) =_9.44 m @ = 40°: Range (Ax) =_[4.5 m @ = 80°: Range (Ax) =_5, Ol m @ = 50°: Range (Ax)=_(4.6 om Add ty @=_/O Range(Ax)= 5.01 m » 0 = 60°: Range (Ax) =_(2.7_m a=_HS Range (Ax)=_J4. 9 m «Measure the distance from the cannon to the target using the tape measure. e Move the target to 21.0 m from the cannon. Attempt to hit the target with three different angles by changing the firing angle and initial velocity. Range (Ax) = 21.0m e= 30° vi=_ 25 m/s Range (Ax)=210m @=__60° v=__15 m/s Vv Range (Ax) = 21.0m O= A projectile’s velocity (v) has an x-component (v,) and a y-component (vy). The x-component (v,) is found by multiplying the magnitude of the velocity by the cosine of the angle, 0. “* Similarity, the y-component of velocity is found by multiplying the magnitude of the velocity by the sine of the angle, 0. Vv, = Vvcos@ v, =vsin So, a projectile fired at 20 m/s at 65° has an x-velocity of |v, = 20 cos 65] or 8.5 m/s. - The projectile would have a y-velocity of |v, = 20sin 65] or 18 m/s. So, the projectile would fire as far as one fred horizontally at 8.5 m/s and as high as one fired straight up at 18 m/s. ‘ A projectile fired at 30 degrees with a velocity. of 15 m/s would | have an x- velocity component of __13 _ m/sanday-velocity comporient of __ 7.5 _ m/s.