1
OPERATOR MATH
Areas and Volumes
Flows
Dosage Formula
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Guidelines and tips
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community
Ask the community for help and clear up your study doubts
University Rankings
Discover the best universities in your country according to Docsity users
Free resources
Our save-the-student-ebooks!
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
Water Treatment Calculations: Volume, Flow, Dosage, Pressure, Schemes and Mind Maps of Public Health Engineering
A collection of mathematical problems relevant to water treatment processes. it covers various calculations, including volume determination for different tank shapes, flow rate calculations, chemical dosage for disinfection, and pressure conversions. The problems are designed to enhance understanding of practical applications in water treatment.
Typology: Schemes and Mind Maps
2024/2025
1 / 73
This page cannot be seen from the preview
Don't miss anything!
Related documents
Partial preview of the text
Download Water Treatment Calculations: Volume, Flow, Dosage, Pressure and more Schemes and Mind Maps Public Health Engineering in PDF only on Docsity!
OPERATOR MATH
Areas and Volumes Flows Dosage Formula
Area Calculation
- Area measurements defines the size or surface of an object. Sometimes an area is described as the X-section (cross section) of an object.
- U.S. units of area:
- Square inches = in²
- Square feet = ft²
- Square yards = yd²
- Square mile = mi.²
Problem # 1
Question: Calculate the area of a circle shown.
5 ft. diameter
Problem # 2
- Question: A circular clarifier has a diameter of 40 ft. What is the surface area of the clarifier?
40 ft.
Volume Calculation
- Volume measurements define the amount of space that an object occupies.
- Some U.S. units of Volume:
- Cubic inches = in³
- Cubic feet = ft³
- Cubic yards = yds³
- Gallons per cu.ft. = 7.48 gals.
- Cylinder = 0.7854 x (d²) x (3rd^ dimension)
- Cylinder = 3.14 x (r²) x (3rd^ dimension)
Problem # 4
- What is the volume of a tank which has a diameter of 10 ft. and a height of 12 ft.?
- Hint: (the 3rd^ dimension is the height of the tank)
12 ft.
10 ft.
Solution to # 5
- Volume = .7854 x (d²) x (3rd^ dimension)
- Volume = .7854 x 1ft. x 1ft. x 5280ft.
- Volume = 4146.9 ft.³ or 4146.9 cu.ft. (Problem # 6)
- How many gallons can the pipe describe in problem # 5 hold if both ends were sealed?
- Hint: 1 cu.ft. = 7.48 gals.
Problem # 7
- How many gallons of water will a storage tank hold if it has a 27ft. Diameter and 40ft. Depth?
40 ft.
27 ft.
CONE
- Calculate the volume of a cone with the dimensions shown on the diagram.
- = Volume of a cone = ⅓ (volume of a cylinder)
- or
- = (0.7854) (D²) (Third dimension) 3
- = (0.7854) (2 ft.) (2 ft.) (3 ft.) 3
- = 3.14 cu. ft.
3 ft.
2 ft.
Problem # 9
- If a spherical tank is 30ft. in diameter, how many gallons of water are required to fill it?
- Formula: (3.14) x Diameter³ x 7.48gls/cuft ( 6 ) 30 ft.
Solution to # 10
- As you can see you have three distinct shapes. Cone, cylinder, & hemisphere. In this case the volumes can be calculated separately, then added together to the total volume.
- Cone= 0.7854 x D² x H x 7.48 gls/cuft 3
- Cylinder= 0.7854 x D² x H x 7.48 gls/cuft
- Hemisphere= 3.14 6 x D³ x 7.48 gls/cuft 2
- Rectangle:
Area = Width x Length Length
Width
# 11 B
- If one roll of carpet covers 80 ft.², how many rolls of carpet are needed?
475 sq. ft.
Problem # 12
- A sedimentation tank is 75 ft. long and 35 ft. wide. What is the surface area of the water tank?