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An in-depth exploration of wave motion, focusing on transverse and longitudinal waves. Learn about their propagation, characteristics, and the factors influencing their velocity. Topics include wavelength, frequency, time period, phase, wave velocity, and the relation between these properties. Discover the differences between transverse and longitudinal waves through examples of water waves, waves in a stretched string, and sound waves.
What you will learn
Typology: Slides
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Wave Motion :- It is the phenomenon of transference of a disturbance from one point to the other with the exchange of energy and momentum, but without the transfer of matter.
Transverse waves ` Longitudinal waves
i. Wavelength ( ) It is the distance travelled by a single wave. It is measured as the distance between two consecutive crests or troughs, in the case of transverse waves and the distance between two consecutive compressions or rarefactions in the case of longitudinal waves. Unit: m ii. Frequency ( ): It is the number of waves traveling per sec. Unit: Hertz iii. Time period (T): It is the time taken by a single wave to travel. Unit: s iv. Phase ( ): It is the argument of sine or cosine function in the equation that represents a wave. Unit: radians v. Amplitude (A): It is the maximum displacement of a particle from its mean position. Unit: m vi. Wave velocity (v): It is the distance traveled by waves in unit time. Unit: m/s
Distance traveled by a single wave = Wavelength () Time taken by a wave = Time period (T) So, wave velocity (v) = Distance / time = / T (1/T = ) v =
Speed of waves
Transverse Waves in a stretched string
v = T/ Where T – tension in the string and - the linear density (mass per unit length of the string)
Speed of longitudinal waves i. Through solids: v = Y/ where Y – Young’s modulus and - the density of the medium ii. Though liquids and gases: v = B/ where B – Bulk modulus and - the density of the medium
Newton’s formula
According to Newton, the propagation of sound in air is isothermal process. So v = Bi/ --------(1) As the process is isothermal, PV = a constant Differentiating we get, PV + VP = 0 P = -PV/V = Bi v = P/ -------------(2) Laplace’s correction
In equation (2), if we substitute the values of P = 1.01 x 10^5 Pa and = 1.29 kg / m^3 at S.T.P, we get velocity of sound as 280 m/s. But the experimental value obtained is nearly 332m/s under these conditions. This discrepancy is removed by Laplace, as given below. According to Laplace, the propagation of sound in air is adiabatic. Hence, v = Ba/ As the process is adiabaic, PV^ = a constant Differentiating we get, PV^ + V-1^ VP = 0 P = -PV/V V-1^ = -PV/V = Ba v = P/ -------------(3)
i. Pressure : When pressure increases, density also increases. Thus the ratio P/ is a constant. So the speed of sound is independent of pressure changes (refer eqn. 3 above), at constant temperature. ii. Temperature : Density = M/V Hence eqn.3 becomes, v = PV/ M v = RT/ M v T Thus the speed of sound is directly proportional to the square root of absolute temperature of air. iii. Density: From the eqn.3, v 1/ i.e., the speed of sound in a medium is inversely proportional to its density. iv. Humidity : When humidity of atmosphere is high, the density of air is low. Thus speed of sound increases. (refer eqn. 3). Hence, the speed of sound in air increases with humidity. v. Wind: The speed sound in air changes according to the direction of wind.
y = 2A sin kx. cosωt
(a). They are not progressive i.e., the crests and troughs do not travel forward. (b). There is not transfer of energy between particles. (c). Particles at different points vibrate with different amplitudes. (d). The amplitude changes from zero to maximum. The points where the amplitude is zero are called nodes and the points where the amplitude is maximum are called antinodes. (e). Every particle, except at nodes, executes S.H.M with the same period. (f). The distance between two consecutive nodes or antinodes is /2.
1. Stretched string: The different frequencies that are formed in the string are called harmonics. The lowest frequency that can be formed in the string is its fundamental frequency and its multiples are called overtones. The standing waves formed in a stretched
First overtone (2nd^ harmonic)
As 1 : 2 : 3 :………….= 1: 2: 3:……, all harmonics are present in the string.
2. Closed pipe: The following diagrams represent the formation of standing waves in a closed pipe. (i) Fundamental freq. (1st^ harmonic) (ii) 1st^ overtone (2nd^ harmonic)
1 : 2 : 3 : ……….= 1: 3: 5…….. Hence only odd harmonics are present in the closed pipe.
3. Open pipe: The following diagrams represent the formation of standing waves in an open pipe. (2) 1st^ overtone (2nd^ harmonic)
Hence, all the harmonics are present in the closed pipe.
It is the phenomenon of periodic variation in the intensity of the wave resulting from the super position of two waves of slightly different frequencies. Graphical treatment to show the formation of beats
Analytical treatment
(Qn. Show that beat frequency is the difference between the parent frequencies) Consider two waves of the same amplitude and slightly different frequencies 1 and 2 given by, y 1 = A sin2 1 t and y 2 = A sin2 2 t When they overlap each other, according to the principle of superposition, Resultant displacement y = y 1 + y 2 y = A sin2 1 t + A sin2 2 t = 2A [sin 2( 1 + 2 )t /2. cos 2( 1 - 2 )t /2] y = 2A cos ( 1 - 2 )t .sin ( 1 + 2 )t Thus the resultant amplitude is given by, R = 2A cos ( 1 - 2 )t ----------------(1) The above equation shows that the amplitude of the resultant wave so formed varies periodically. As intensity is directly proportional to the square of amplitude (I R^2 ), there is periodic variation of intensity of the wave. Intensity is maximum, when R is maximum. i.e., cos ( 1 - 2 )t = 1. i.e., ( 1 - 2 )t = 0, , 2,……..
So, intensity is max. at the instants t = 0, 1/ ( 1 - 2 ), 2 / ( 1 - 2 )………. the time interval between two maxima = 1/ ( 1 - 2 ) i.e., Beat frequency [the number of beats per second] () = ( 1 - 2 ) Intensity is minimum, when R is minimum. i.e., cos ( 1 - 2 )t = 0. i.e., ( 1 - 2 )t = /2, 3/2 ,5/2 ……..
So, intensity is min. at the instants t = 1/ 2( 1 - 2 ), 3 / 2( 1 - 2 ), 5 / 2( 1 - 2 ),………. the time interval between two minima = 1/ ( 1 - 2 ) Thus again, Beat frequency [the number of beats per second] () = ( 1 - 2 )
This shows that beat frequency is the difference between parent frequencies.