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reporte de laboratorio para fisica, Study notes of Physics

Pontificia Universidad Católica de Puerto Rico - MayaguezPhysics
Prof. Juan Luis

reporte de laboratorio para fisica

Typology: Study notes

2024/2025

Uploaded on 07/01/2025

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LABORATORIO DE FÍSICA I
(MA466)
LB09: COLISIONES
Apellidos y nombres:
1. Maldonado Marin Jaime Sebastian
2. Palacios Yovera, Jean Franco
3. León Quilca, María del Pilar
4. Sánchez Martel, César Mathias
Grupo de Datos: ____1_____
DESARROLLO DEL REPORTE:
1. Complete la Tabla 1 con el grupo de datos asignado,
Tabla 1
Billa 1 (incidente) Billa 2 (blanco)
H (cm) R1 (cm) R2 (cm) R3 (cm) R’1 (cm) R’2 (cm) R’3 (cm)
h1106,20 52,10 52,00 51,05 50,05 50,50 49,45
h2106,20 42,30 43,15 42,35 40,15 39,50 39,00
h3106,20 27,40 27,10 26,55 26,50 25,65 26,70
2. Deduzca la expresión que permite determinar la rapidez de impacto de la billa 1
v1 (antes de la colisión) y la rapidez de salida de la billa 2 v’2 (después de la
colisión), Argumente su respuesta, Calcule los resultados y complete la Tabla 2,
∆ y=vo y∗t+1
2∗g∗t2
∆ y=H ; vo y =0m
s
t=
√
2H
g
∆ x=v1∗t → v 1=R
t
v1=Rprom ∙
√
g
2H
v '2=Rprom
'∙
√
g
2H
1
pf3

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LABORATORIO DE FÍSICA I

(MA466)

LB09: COLISIONES

Apellidos y nombres:

**1. Maldonado Marin Jaime Sebastian

  1. Palacios Yovera, Jean Franco
  2. León Quilca, María del Pilar
  3. Sánchez Martel, César Mathias**

Grupo de Datos: ____1_____

DESARROLLO DEL REPORTE:

1. Complete la Tabla 1 con el grupo de datos asignado,

Tabla 1

Billa 1 (incidente) Billa 2 (blanco)

H (cm) R 1

(cm) R 2

(cm) R 3

(cm) R’ 1

(cm) R’ 2

(cm) R’ 3

(cm)

h 1

106,20 52,10 52,00 51,05 50,05 50,50 49,

h 2

106,20 42,30 43,15 42,35 40,15 39,50 39,

h 3

106,20 27,40 27,10 26,55 26,50 25,65 26,

2. Deduzca la expresión que permite determinar la rapidez de impacto de la billa 1

v 1

(antes de la colisión) y la rapidez de salida de la billa 2 v ’ 2

(después de la

colisión), Argumente su respuesta , Calcule los resultados y complete la Tabla 2,

∆ y = v

o y

∗ t +

∗ g ∗ t

2

∆ y = H ; v

o y

m

s

t =

2 H

g

∆ x = v

1

∗ t → v

1

R

t

v

1

= R

prom

g

2 H

v '

2

= R

prom

'

g

2 H

Tabla 2

Billa 1 (incidente) Billa 2 (blanco)

H (m) R prom

(m) v 1

(m/s) R’ prom

(m) v ' 2

(m/s)

h

1

1,06 0,5171 0,1111 0,5000 1,

h 2

1,06 0,4260 0,9552 0,3955 0,

h 3

1,06 0,2701 0,5062 0,2628 0,

3. Presente la gráfica v ’ 2

vs v 1

realizada,

4. Deduzca la expresión que permite determinar el coeficiente de restitución ( e ) en

función de la pendiente de la gráfica obtenida, argumente su respuesta , Calcule y

presente el resultado correctamente,

e =

v ´

1

− v ´

2

v

2

− v

1

; v

2

m

s

v

1

− e ∗ v

1

  • v ´

2

  • v ´

2

v ´

2

(

e + 1

)

∗ v

1

y = pendiente ∗ x + b → e = 2 ∗ pend − 1

e = 2 × pend − 1

e = 2 × 0,9485− 1 =0,897 0

Escriba la expresión para determinar la incertidumbre del coeficiente de

restitución ( e ), Calcule y presente el resultado correctamente,

∆ e = 2 ∆ pend = 2 × pend. ( 1 − R

2

∆ e = 2 × 0,