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series in calculus explained
Typology: Cheat Sheet
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Convergence
A sequence {an} converges if lim an exists and is finite.
Squeeze theorem
If bn ≤ an ≤ cn for all values of n, and lim bn = lim cn = L, then it implies that lim an = L.
Other Useful facts
an converges to zero if and only if |an| also converges to zero.
When n is large, ln(n) < np^ < an^ < n! < nn
SERIES
Partial sums
sN =
n=
an
Convergence
A series is convergent when the limit of partial sums exists, ∑ an = lim N →∞
sN
otherwise it is divergent.
A series is absolutely convergent when
|an| is convergent.
A series is conditionally convergent when
|an| is divergent but
an is convergent.
Geometric series ∑ arn−^1 converges when |r| < 1, otherwise diverges.
When convergent, the sum is equal to
a 1 − r
p-series
∑ (^1)
np^
converges when p > 1, otherwise diverges.
Divergence Test
If lim an 6 = 0, then the series
an is divergent.
Integral Test
If an = f (n) when f (x) is a positive, continuous, eventually decreasing function, then
∑^ ∞
n=
an converges ⇐⇒
1
f (x)dx converges
Comparison Test
Suppose an and bn are two positive sequences, with an ≤ bn for all n > N for some number N.
If
bn is convergent, then so is
an.
If
an is divergent, then so is
bn.
Limit Comparison Test
Suppose that an and bn are two positive sequences, and lim a bnn = c.
bn converges.
bn converges, then
an converges.
bn diverges, then
an diverges.
Ratio Test
Suppose that lim
an+ an
an is absolutely convergent.
an is divergent.
Root Test
Suppose that lim |an|^1 /n^ = L.
an is absolutely convergent.
an is divergent.
Alternating Series Test
For series of the form
(−1)nbn, where bn is a positive and eventually decreasing sequence, then ∑ (−1)nbn converges ⇐⇒ lim bn = 0
Definitions ∑^ ∞
n=
cnxn^ OR
n=
cn(x − a)n
Radius of convergence: The radius is defined as the number R such that the power series converges if |x−a| < R, and diverges if |x − a| > R.
Interval of convergence: I = interval of values of x for which the power series is convergent. Note that the length of the interval is twice the radius of convergence..
MacLaurin Series
f (x) =
n=
f (n)(0) n!
xn
Taylor Series
f (x) =
n=
f (n)(a) n!
(x − a)n