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Review Sheet for Calculus 2 Sequences and Series, Cheat Sheet of Calculus

series in calculus explained

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Review Sheet for Calculus 2 Sequences and Series
SEQUENCES
Convergence
A sequence {an}converges if lim anexists and is finite.
Squeeze theorem
If bnancnfor all values of n, and lim bn= lim cn=L,
then it implies that lim an=L.
Other Useful facts
anconverges to zero if and only if |an|also converges to zero.
When nis large, ln(n)< np< an< n!< nn
SERIES
Partial sums
sN=
N
X
n=1
an
Convergence
A series is convergent when the limit of partial sums exists,
Xan= lim
N→∞
sN
otherwise it is divergent.
A series is absolutely convergent when P|an|is convergent.
A series is conditionally convergent when P|an|is divergent
but Panis convergent.
Geometric series
Parn1converges when |r|<1, otherwise diverges.
When convergent, the sum is equal to a
1r.
p-series
X1
npconverges when p > 1, otherwise diverges.
Divergence Test
If lim an6= 0, then the series Panis divergent.
Integral Test
If an=f(n) when f(x) is a positive, continuous, eventually
decreasing function, then
X
n=1
anconverges Z
1
f(x)dx converges
Comparison Test
Suppose anand bnare two positive sequences, with anbn
for all n > N for some number N.
If Pbnis convergent, then so is Pan.
If Panis divergent, then so is Pbn.
Limit Comparison Test
Suppose that anand bnare two positive sequences, and
lim an
bn=c.
If c > 0 is a finite number, then
Xanconverges Xbnconverges.
If c= 0 and Pbnconverges, then Panconverges.
If c=and Pbndiverges, then Pandiverges.
Ratio Test
Suppose that lim
an+1
an
=L.
If L < 1, then Panis absolutely convergent.
If L > 1, then Panis divergent.
If L= 1, then the test is inconclusive.
Root Test
Suppose that lim |an|1/n =L.
If L < 1, then Panis absolutely convergent.
If L > 1, then Panis divergent.
If L= 1, then the test is inconclusive.
Alternating Series Test
For series of the form P(1)nbn, where bnis a positive and
eventually decreasing sequence, then
X(1)nbnconverges limbn= 0
POWER SERIES
Definitions
X
n=0
cnxnOR
X
n=0
cn(xa)n
Radius of convergence: The radius is defined as the number R
such that the power series converges if |xa|< R, and diverges
if |xa|> R.
Interval of convergence:I= interval of values of xfor which
the power series is convergent. Note that the length of the
interval is twice the radius of convergence..
MacLaurin Series
f(x) =
X
n=0
f(n)(0)
n!xn
Taylor Series
f(x) =
X
n=0
f(n)(a)
n!(xa)n
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Review Sheet for Calculus 2 Sequences and Series

SEQUENCES

Convergence

A sequence {an} converges if lim an exists and is finite.

Squeeze theorem

If bn ≤ an ≤ cn for all values of n, and lim bn = lim cn = L, then it implies that lim an = L.

Other Useful facts

an converges to zero if and only if |an| also converges to zero.

When n is large, ln(n) < np^ < an^ < n! < nn

SERIES

Partial sums

sN =

∑^ N

n=

an

Convergence

A series is convergent when the limit of partial sums exists, ∑ an = lim N →∞

sN

otherwise it is divergent.

A series is absolutely convergent when

|an| is convergent.

A series is conditionally convergent when

|an| is divergent but

an is convergent.

Geometric series ∑ arn−^1 converges when |r| < 1, otherwise diverges.

When convergent, the sum is equal to

a 1 − r

p-series

∑ (^1)

np^

converges when p > 1, otherwise diverges.

Divergence Test

If lim an 6 = 0, then the series

an is divergent.

Integral Test

If an = f (n) when f (x) is a positive, continuous, eventually decreasing function, then

∑^ ∞

n=

an converges ⇐⇒

1

f (x)dx converges

Comparison Test

Suppose an and bn are two positive sequences, with an ≤ bn for all n > N for some number N.

If

bn is convergent, then so is

an.

If

an is divergent, then so is

bn.

Limit Comparison Test

Suppose that an and bn are two positive sequences, and lim a bnn = c.

  • If c > 0 is a finite number, then ∑ an converges ⇐⇒

bn converges.

  • If c = 0 and

bn converges, then

an converges.

  • If c = ∞ and

bn diverges, then

an diverges.

Ratio Test

Suppose that lim

an+ an

∣ =^ L.

  • If L < 1, then

an is absolutely convergent.

  • If L > 1, then

an is divergent.

  • If L = 1, then the test is inconclusive.

Root Test

Suppose that lim |an|^1 /n^ = L.

  • If L < 1, then

an is absolutely convergent.

  • If L > 1, then

an is divergent.

  • If L = 1, then the test is inconclusive.

Alternating Series Test

For series of the form

(−1)nbn, where bn is a positive and eventually decreasing sequence, then ∑ (−1)nbn converges ⇐⇒ lim bn = 0

POWER SERIES

Definitions ∑^ ∞

n=

cnxn^ OR

∑^ ∞

n=

cn(x − a)n

Radius of convergence: The radius is defined as the number R such that the power series converges if |x−a| < R, and diverges if |x − a| > R.

Interval of convergence: I = interval of values of x for which the power series is convergent. Note that the length of the interval is twice the radius of convergence..

MacLaurin Series

f (x) =

∑^ ∞

n=

f (n)(0) n!

xn

Taylor Series

f (x) =

∑^ ∞

n=

f (n)(a) n!

(x − a)n