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HW 2 Solutions Material Type: Notes; Class: Advanced Statistical Inference; Subject: Statistics; University: California State University-East Bay; Term: Fall 2012;
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Stat. 6304 (Fall, 2012) HW 2 Solutions
4.6 a. 1 in 4 (or 0.25) b. 1 in 106000.
4.14 600/12000 = 1/20=0.05.
a. P (A) = 4/23. b. P (B) = 0. c. Yes, the events are mutually exclusive. A manager cannot collect less than 80% and between 85 and 89% simultaneously. d. P (meets standard) = (2 + 13)/23 = 15/ 23.
a. P (woman) = 0.4; P (man) = 1 − P (woman) = 1 − 0 .4 = 0.6. b. P (2consecutive women) = P (woman1)P (woman2) = (0.4)(0.4) = 0.16. Note that the first = is due to independence.
4.42 P (A) = 0.55 and P (B|A) > 1 /3.
a. 30/ b. 21/ c. P (not Anglo − Australian) = 1 − P (Anglo − Australian) = 1 − 63 /139 = 76/139. d. P (close contact ∪ Asian) = P (close contact)+P Asian)−P (close contact ∩ Asian) = 21+46 139 − 1 = 66/139. e. P (little or no contact|Asian) = P (little or no contact ∩ Asian) P (Asian)
f. P (little or no contact|Anglo − Australian) =
P (little or no contact ∩ Anglo − Australian) P (Anglo − Australian)
=
g. Asians are most likely to have little or no contact with mentally ill people. (Note that this means that etnicity is not independent of “little or no contact with mentally ill”.
a. 21/22. b. P (“professor” correct) = 1 − 8 /22 = 14/ 22. c. P ( misspell “Gandhi” ∪ “Khaki”) = P (misspell “Gandhi”) + P (misspell “khaki”) − P (misspell both) = 19 /22 + 5/ 22 − 3 /22 = 21/ 22.
4.74 Events A (pregnant) and B (test positive and not pregnant) are mutually exclusive. Also, events B and C (test negative and pregnant) are mutually exclusive.