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The solution to quiz 6 in math 2203, where students are required to evaluate the line integral of a conservative vector field f(x, y) = 32j over the parabolic curve y = x² from (0, 0) to (1, 1). The solution utilizes the fundamental theorem of line integrals and the definition of line integrals.
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MATH 2203 ñQuiz 6 (Version 1) Solution November 20, 2009
Let F be the vector Öeld
F (x; y) = 32 j
and let C be the parabolic curve y = x^2 beginning at the point (0; 0) and ending at the point (1; 1). Evaluate the line integral Z
C
F dr.
You must include all details of your work. Solution: The easiest way to do this is to use the Fundamental Theorem of Line Integrals: The vector Öeld F (x; y) = 32 j is conservative and has potential function f (x; y) = 32 y. Thus Z
C
F dr =
C
rf dr = f (1; 1) f (0; 0) = 32 0 = 32.
Now we show how to do the integral using the deÖnition of line integrals: The curve C can be parameterized as
r (t) = ti + t^2 j 0 t 1
from which we see that r^0 (t) = i + 2tj
and F (r (t)) r^0 (t) = ( 32 j) (i + 2tj) = 64 t.
Thus (^) Z
C
F dr =
C
F (r (t)) r^0 (t) dt =
0