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Study Notes on Electromagnetic Waveguides - Electromagnetism | PHY 712, Study notes of Electromagnetism and Electromagnetic Fields Theory

Material Type: Notes; Professor: Holzwarth; Class: Electromagnetism; Subject: Physics; University: Wake Forest University; Term: Spring 2000;

Typology: Study notes

Pre 2010

Uploaded on 08/18/2009

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April 5, 2000
Notes for Lecture #30
Electromagnetic wave guides
In order to understand the op eration of a wave guide, wemust rst learn how electromagnetic
waves behave in a dissipative medium. Aplanewave solution to Maxwell's equations of the
form:
E
=
E
0
e
ik
^
k
r
i!t
and
B
=
k
!
^
k
E
0
e
ik
^
k
r
i!t
(1)
for the electric and magnetic elds, with the wave vector
k
satisfying the relation:
k
2
=
!
2
"
R
+
i
I
:
(2)
We can determine the complex wavevector
k
r
+
ik
i
according to
k
r
=
p
R
2
+
I
2
+
R
2
!
1
=
2
and
k
i
=
p
R
2
+
I
2
R
2
!
1
=
2
(3)
The form of the frequency dependent constants
R
and
I
depend on the materials. For the
Drude model at low frequency (Eq. 7.56),
R
=
!
2
"
b
and
I
=
!
,for example. The
value of
k
i
determines the rate of decay of the eld amplitudes in the vicinity of the surface,
with the skin depth given by
Æ
1
=k
i
. In the limit that
I R
,as in the case of a good
conductor at low frequency,
Æ
(2
=
(
!
))
1
=
2
.
For an "ideal" conductor
I!1
, so that the elds are conned to the surface. Because of
the eld continuity conditions at the surface of the conductor, this means that,
B
tangential
6
=0
(because there can be a surface current),
E
normal
6
= 0 (because there can be a surface charge),
and
B
normal
=0.
Suppose we construct a wave guide from an "ideal" conductor, designating
^z
as the propa-
gation direction. We will assume that the elds take the form:
E
=
E
(
x; y
)e
ikz
i!t
and
B
=
B
(
x; y
)e
ikz
i!t
(4)
inside the pipe, where now
k
and
"
are assumed to be real. Assuming that there are no sources
inside the pipe, the elds there must satisfy Maxwell's equations (8.16) which expand to the
following :
@B
x
@x
+
@B
y
@y
+
ikB
z
=0
:
(5)
@E
x
@x
+
@E
y
@y
+
ikE
z
=0
:
(6)
@E
z
@y
ikE
y
=
i!B
x
:
(7)
pf2

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April 5, 2000

Notes for Lecture

Electromagnetic wave guides

In order to understand the op eration of a wave guide, we must rst learn how electromagnetic waves b ehave in a dissipative medium. A plane wave solution to Maxwell's equations of the form:

E = E 0 eik^ ^kri! t and B =

k !

^k  E 0 eik^ ^kri!^ t^ (1)

for the electric and magnetic elds, with the wave vector k satisfying the relation:

k 2 =! 2 "  R + iI : (2)

We can determine the complex wavevector kr + iki according to

kr =

p

R^2 + I 2 + R

and ki =

p

R^2 + I 2 R

The form of the frequency dep endent constants R and I dep end on the materials. For the

Drude mo del at low frequency (Eq. 7.56), R =! 2 "b and I =!  , for example. The

value of ki determines the rate of decay of the eld amplitudes in the vicinity of the surface,

with the skin depth given by Æ  1 =ki. In the limit that I  R, as in the case of a go o d

conductor at low frequency, Æ  (2=(!  ))^1 =^2.

For an "ideal" conductor I! 1 , so that the elds are con ned to the surface. Because of

the eld continuity conditions at the surface of the conductor, this means that, Btangential 6 = 0

(b ecause there can b e a surface current), Enormal 6 = 0 (b ecause there can b e a surface charge),

and Bnormal = 0.

Supp ose we construct a wave guide from an "ideal" conductor, designating ^z as the propa- gation direction. We will assume that the elds take the form:

E = E(x; y )eik^ z^ i!^ t^ and B = B(x; y )eik^ z^ i!^ t^ (4)

inside the pip e, where now k and " are assumed to b e real. Assuming that there are no sources inside the pip e, the elds there must satisfy Maxwell's equations (8.16) which expand to the following : @ Bx @ x

@ By @ y

  • ik Bz = 0 : (5)

@ Ex @ x

@ Ey @ y

  • ik Ez = 0 : (6)

@ Ez @ y

ik Ey = i! Bx : (7)

ik Ex

@ Ez @ x

= i! By : (8)

@ Ey @ x

@ Ex @ y

= i! Bz : (9)

@ Bz @ y

ik By = i"! Ex : (10)

ik Bx

@ Bz @ x

= i"! Ey : (11)

@ By @ x

@ Bx @ y

= i"! Ez : (12)

Combining Faraday's Law and Amp ere's Law, we nd that each eld comp onent must satisfy a two-dimensional Helmholz equation:

@ 2 @ x^2

@ y 2

k 2 + "! 2

Ex (x; y ) = 0 ; (13)

with similar expressions for each of the other eld comp onents. For the rectangular wave guide discussed in Section 8.4 of your text a solution for a TE mo de can have:

Ez (x; y )  0 and Bz (x; y ) = B 0 cos

 m x

a

cos

 n y

b

with k 2  k 2 mn = "! 2

m a

 n

b

. From this result and Maxwell's equations, we

can determine the other eld comp onents. For example Eqs. (7-8) simplify to

Bx =

k !

Ey and By =

k !

Ex : (15)

These results can b e used in Eqs. (10-11) to solve for the elds Ex and Ey and Bx and By :

Ex =

k

By =

i!

k 2 "! 2

@ Bz @ y

i!

m a

n b

 2 ^

n b

B 0 cos

 m x

a

sin

 n y

b

and

Ey =

k

Bx =

i!

k 2 "! 2

@ Bz @ x

i!

m a

n b

 2 ^

n a

B 0 sin

m x a

cos

n y b

One can check this result to show that these results satisfy the b oundary conditions. For example, Etangential = 0 is satis ed since Ex (x; 0) = Ex (x; b) = 0 and Ey (0; y ) = Ey (a; y ) = 0.

This was made p ossible cho osing rBz csurface  n^ = 0, where n^ denotes a unit normal vector

p ointing out of the wave guide surface.