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The average rate of change of function over the interval ..., Slides of Algebra

Create 2 points using the given x values. Average rate of change is just the slope of the line that connects the points. = −4 Answer: Average Rate of Change = ...

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1.4 Rates of Change (Minimum Homework: 1, 3, 5, 7, 9, 11, 15, 19, 21, 25)
Average rate of change:
The average rate of change of function 𝑓 over the interval (𝑎, 𝑏) is
given by this equation:
𝑨𝒗𝒆𝒓𝒂𝒈𝒆 𝒓𝒂𝒕𝒆 𝒐𝒇 𝒄𝒉𝒂𝒏𝒈𝒆 = 𝒇(𝒃)−𝒇(𝒂)
𝒃−𝒂
Average rate of change is a measure of how much a function
changes per unit, on average, over that interval.
Average rate of change is just the slope of the straight line
connecting the interval's endpoints on the graph of the function.
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Download The average rate of change of function over the interval ... and more Slides Algebra in PDF only on Docsity!

1.4 Rates of Change (Minimum Homework: 1, 3, 5, 7, 9, 11, 15, 19, 21, 25)

Average rate of change:

The average rate of change of function 𝑓 over the interval (𝑎, 𝑏) is

given by this equation:

𝒇(𝒃)−𝒇(𝒂)

𝒃−𝒂

  • Average rate of change is a measure of how much a function

changes per unit, on average, over that interval.

  • Average rate of change is just the slope of the straight line

connecting the interval's endpoints on the graph of the function.

Average rate of example 1 :

Find the average rate of change for each function over the given

interval. Sketch a graph to model your answer. (You may use your

calculator obtain the graph, be sure to label the necessary points.)

2

  • 4 𝑥 − 5 between 𝑥 = 1 𝑎𝑛𝑑 𝑥 = 3

Create 2 points using the given x values.

2

Creates the point: ( 1 , − 3 )

2

Creates the point: ( 3 , − 11 )

Average rate of change is just the slope of the line that connects the

points.

− 11 −(− 3 )

3 − 1

− 8

2

Answer: Average Rate of Change = −𝟒

Average rate of change example 2 :

At 10 AM a car’s odometer read 10,300 miles. At noon, the car’s

odometer read 10,420 miles. What is the car’s average rate of change

measured in miles per hour?

We need to create two points.

Since we are asked to find the average rate of change in miles per hour

𝑥 − 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 of the points must be time in hours (hours are

mentioned second)

𝑦 − 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 of the points must be distance in miles (miles are

mentioned first)

These are the points needed: ( 10 , 10300 ) ( 12 , 10420 )

10420 − 10300 (𝑚𝑖𝑙𝑒𝑠)

12 − 10 (ℎ𝑜𝑢𝑟𝑠)

120 𝑚𝑖𝑙𝑒𝑠

2 ℎ𝑜𝑢𝑟𝑠

Answer: Average Rate of Change (velocity): 𝟔𝟎 𝒎𝒑𝒉

  • Average rate of change tells us the average rate at which a

function changes over an interval.

  • The average rate of change only tells us an average change

between two values of x. It gives no specific information in-

between the two values of 𝑥.

▪ That is, we have no idea how the function behaves at any

specific instant in the interval between the given values of x.

  • In the car example we computed the average rate of change

(velocity) was 60 𝑚𝑖𝑙𝑒𝑠 𝑝𝑒𝑟 ℎ𝑜𝑢𝑟 over the 2-hour trip. This is an

average speed for the entire trip. This does not mean the car

traveled at precisely 60 𝑚𝑝ℎ for the entire trip. This is just the

average speed. In fact, it likely went faster than 60 𝑚𝑝ℎ at times

and slower than 60 𝑚𝑝ℎ at other times. The car could have been

stopped for a chunk of time.

▪ We need to calculate the car’s instantaneous rate of

change to know its speed (velocity) at a specific

moment.

Calculus is needed to compute instantaneous rate of change.

Instantaneous rate of change of a function 𝑓 at 𝑥 = 𝑎 : Is the average

rate of change of the function 𝑓 at 𝑥 = 𝑎.

  • The instantaneous rate is essentially the average rate

of change over the interval (𝑎, 𝑎 + ℎ).

  • To find the instantaneous rate of change, we take the

limit as ℎ 𝑎𝑝𝑝𝑟𝑜𝑎𝑐ℎ𝑒𝑠 0.

  • The instantaneous rate of change is the average rate of

change at a single point, since h is changed to zero and

we get the interval

This is the formula to compute instantaneous rate of change of a

function 𝑓 𝑤ℎ𝑒𝑛 𝑥 = 𝑎.

𝐼𝑛𝑠𝑡𝑎𝑛𝑡𝑎𝑛𝑒𝑜𝑢𝑠 𝑟𝑎𝑡𝑒 𝑜𝑓 𝑐ℎ𝑎𝑛𝑔𝑒 = lim

ℎ→ 0

𝑓(𝑎+ℎ)−𝑓(𝑎)

(𝑎+ℎ)−𝑎

= lim

ℎ→ 0

𝑓(𝑎+ℎ)−𝑓(𝑎)

▪ Instantaneous rate of change is a measure of the slope of the line

connecting the points: (𝑎, 𝑓

We will use the word DERIVATIVE very often this semester.

  • The terms instantaneous rate of change and derivative have the

same definition and they are interchangeable words.

  • The value of a derivative of function 𝑓 when 𝑥 = 𝑎 is just the

instantaneous rate of change of the function 𝑓 at 𝑥 = 𝑎

This is the formula to compute derivative of a function 𝑓 𝑎𝑡 𝑥 = 𝑎.

Derivative = 𝑓

(𝑎) = lim

ℎ→ 0

𝑓

( 𝑎+ℎ

) −𝑓(𝑎)

(𝑎+ℎ)−𝑎

= lim

ℎ→ 0

𝑓

( 𝑎+ℎ

) −𝑓(𝑎)

  • We use the symbol

  • A derivative is a measure of the slope of the line connecting the

points: (𝑎, 𝑓

I nstantaneous rate of change example 2:

A pebble is dropped from a cliff, 288 𝑓𝑜𝑜𝑡 cliff. The pebble takes 3

seconds to hit the ground.

The formula: f ( t )= 288 − 32 𝑡

2

Can be used to calculate the pebbles

height of the ground in 𝑓 feet 𝑡 − 𝑠𝑒𝑐𝑜𝑛𝑑𝑠 after it is dropped.

a) Calculate the average rate of change (average speed) in feet per

second of the pebble for the 3 seconds it takes to hit the ground.

We need to create two points.

Since we are asked to find the average rate of change (velocity) in feet

per second

𝑥 − 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 of the points must be time in seconds (hours are

mentioned second)

𝑦 − 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 of the points must be height in feet (feet are

mentioned first)

These are the points needed:

(at 0 seconds the pebble is 288 feet high)

( 3 , 0 ) (at 3 seconds the pebble is on the ground.

0 − 288 (𝑓𝑒𝑒𝑡)

3 − 0 (𝑠𝑒𝑐𝑜𝑛𝑑𝑠)

− 288 𝑓𝑒𝑒𝑡

3 𝑠𝑒𝑐𝑜𝑛𝑑𝑠

Answer: Average Rate of Change (average speed):

−𝟗𝟔 𝒇𝒆𝒆𝒕 𝒑𝒆𝒓 𝒔𝒆𝒄𝒐𝒏𝒅 (answer is negative since the pebble is falling)

b) Calculate the instantaneous rate of change in feet per second

(velocity) of the pebble at t = 3 seconds.

Create 2 points

Use 𝑥 = 3 as the x-coordinate of the first point

Find the y-coordinate of the first point:

2

First point: ( 3 , 0 )

Use 3 + ℎ as the x-coordinate of the second point.

Find the y-coordinate of the second point:

2

2

2

2

Second point: ( 3 + ℎ, −192ℎ − 32 ℎ

2

lim

ℎ→ 0

192ℎ− 32 ℎ

2

− 0 (𝑓𝑒𝑒𝑡)

ℎ (𝑠𝑒𝑐𝑜𝑛𝑑𝑠)

= lim

ℎ→ 0

ℎ(− 192 −32ℎ)(𝑓𝑒𝑒𝑡)

ℎ (𝑠𝑒𝑐𝑜𝑛𝑑𝑠)

= lim

ℎ→ 0

Answer: The pebble’s velocity (instantaneous rate of change) is

−𝟏𝟗𝟐 𝒇𝒆𝒆𝒕 𝒑𝒆𝒓 𝒔𝒆𝒄𝒐𝒏𝒅 when it hits the ground. (The negative sign

indicates the pebble is falling.)

(Minimum Homework: 1, 3, 5, 7, 9, 11, 15, 19, 21, 25)

#1-8: Find the average rate of change for each function over the given

interval. Sketch a graph to model your answer. (You may use your

calculator obtain the graph, be sure to label the necessary points.)

  1. f(x) = √𝑥 − 5 between x = 9 and x = 14

  2. f(x) = √

𝑥 + 2 between x = 2 and x = 7

Answer: Average rate of change =

1

5

(Minimum Homework: 1, 3, 5, 7, 9, 11, 15, 19, 21, 25)

#1-8: Find the average rate of change for each function over the given

interval. Sketch a graph to model your answer. (You may use your

calculator obtain the graph, be sure to label the necessary points.)

  1. s(t) = 2

t

between t = 0 and t = 2

  1. s(t) = 3

t

between t = 0 and t = 1

Answer: Average rate of change = 2

(Minimum Homework: 1, 3, 5, 7, 9, 11, 15, 19, 21, 25)

  1. A climber is on a hike. After 2 hours he is at an altitude of 400 feet.

After 6 hours, he is at an altitude of 700 feet. What is the average rate

of change in the climber’s height?

  1. A scuba diver is 30 feet below the surface of the water 10 seconds

after he entered the water and 50 feet below the surface after 40

seconds. What is the scuba divers’ average rate of change in the diver’s

depth measured in feet per second? (write answer as a reduced

fraction)

Answer: The scuba divers’ average rate of change is

2

3