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The relationship between the pressure and volume of a confined gas is inversely proportional. The data collected and the graphs plotted prove this ...
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PURPOSE: The purpose of this lab was to determine the relationship between the pressure and volume of a confined gas.
DATA AND CALCULATIONS TABLE:
V – 1.7 mL Corrected Volume (mL)
Pressure (atm) 1/Volume (mL) Constant, k (P/V or P•V)
PRESSURE vs. VOLUME
0
1
2
3
0 5 10 15 20 25 VOLUME (mL)
PRESSURE (atm)
PRESSURE vs. 1/VOLUME
0
1
2
3
0 0.05 0.1 0.15 0. 1/VOLUME (1/m L)
PRESSURE (atm)
If the volume is doubled from 5.0 mL to 10.0 mL, my data shows that the pressure will decrease by a factor of
If the volume is halved from 20.0 mL to 10.0 mL, what does your data show happens to the pressure?
If the volume is halved from 20.0 mL to 10.0 mL, my data shows that the pressure will increase by a factor of 2.
If the volume is tripled from 5.0 mL to 15.0 mL, my data shows that the pressure will decrease by a factor of 3.
The relationship between the pressure and volume of a confined gas is inversely proportional. The data collected and the graphs plotted prove this relationship. The shapes of the curves in the graphs and the fact that when the volume decreases, the pressure increases (vice-versa), also prove the inverse relationship.
If the volume of the syringe was 40.0 mL, there would be no pressure exerted on the pressure sensor because the volume of the gas would be too large. From the data collected, one can see that when the volume increased from 5.0 mL to 15.0 mL, the gas pressure decreased by a factor of 2. If a gas would have a volume of 40.0 mL, then the gas pressure would have to decrease by a factor of 2 as well. However, when extrapolating an extended graph with 40.0 mL of gas volume present, one would find that the pressure would be so close to zero that it would not be readable using a CBL. The pressure would be such a small number.
Based on the data, the pressure would be________if the volume of the syringe was decreased to 2.5 mL.
Taking into consideration Boyle’s Law, P 1 V 1 /T 1 =P 2 V 2 /T 2 , the only assumed constant would be the temperature.
Based on question 4, k=P•V is used, because the relationship of pressure vs. volume of a confined gas is inversely proportional. See Data and Calculations Table on previous page.