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Chm151: General Chemistry I Lab Manual and Data Sheet for Hydrochloric Acid + Sodium Hydroxide Calorimetry
Typology: Lab Reports
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THERMOCHEMISTRY II: H ESS ’ S LAW | 83
DISCUSSION:
In this part of the experiment, you will use your calorimeter to measure the heat released by three related reactions. Because two of the reactions sum up to give the third reaction, you can use the set of measurements to check Hess’s law of heat summation.
In the first reaction, solid sodium hydroxide dissolves in water:
NaOH (^) (s) → Na+(aq) + OH – (aq) ∆H 1 =?
In the second reaction, aqueous solutions of sodium hydroxide and hydrochloric acid react to form water and aqueous sodium chloride:
Na+(aq) + OH –^ (aq) + H+(aq) + Cl – (aq) → H 2 O (^) (l) + Na+(aq) + Cl – (aq) ∆H 2 =?
In the third reaction, solid sodium hydroxide reacts with aqueous hydrochloric acid to form water and aqueous sodium chloride:
NaOH (^) (s) + H+(aq) + Cl – (aq) → H 2 O (^) (l) + Na+(aq) + Cl – (aq) ∆H 3 =?
As in the first part of the Thermochemistry lab, you will use an EPS cup supported in a beaker as the calorimeter. Although this assembly is not a perfect insulator, if we assume that the heat losses are not significantly different from one trial to the next, we can expect valid comparisons.
PROCEDURE:
Reaction 1
84 | CHM151LL: G ENERAL C HEMISTRY I LAB MANUAL
Reaction 2
Reaction 3
Data Analysis
q = m·CP·∆T Assume that the 3 dilute solutions have the same specific heat as H 2 O ( i.e. CP = 4.18 J/g·°C).
86 | CHM151LL: G ENERAL C HEMISTRY I LAB MANUAL
Data
Reaction 1 NaOH(s) + H 2 O(l)
Reaction 2 NaOH(aq) + HCl(aq)
Reaction 3 NaOH(s) + HCl(aq)
vial + NaOH mass g g
empty vial mass g g
NaOH used g mL g
solution mass, m g g g
maximum temperature, T 2 °C °C °C
initial temperature. T 1 °C °C °C
temperature difference, ∆T °C °C °C
Calculations
heat absorbed q = m·CP·∆T kJ kJ kJ
enthalpy change, ∆H kJ kJ kJ
molar enthalpy of rxn, ∆Hrxn kJ/mol kJ/mol kJ/mol
% difference %
a. Reaction 1 ∆H 1 = kJ/mol
b. Reaction 2 ∆H 2 = kJ/mol
c. Reaction 1 + Reaction 2 ∆H1+2 = kJ/mol
d. Reaction 3 ∆H 3 = kJ/mol