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Uniform Circular Motion - General Physics I - Lecture Slides, Slides of Physics

Following points are the summary of these Lecture Slides : Uniform Circular Motion, Special Case, Radius of Motion, Constant, Velocity Changes, Speed, Object, accelerated, Circular Motion, Centripetal acceleration

Typology: Slides

2012/2013

Uploaded on 07/26/2013

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Uniform Circular Motion
UCM, a special case of 2-D motion where:
The radius of motion (r) is constant
The speed (v) is constant
The velocity changes as object continually changes
direction
Since is changing (v is not but direction is), the object
must be accelerated:
The direction of the acceleration vector is always toward the
center of the circular motion and is referred to as the
centripetal acceleration
The magnitude of centripetal acceleration:
ˆˆ
y
x
cx y
v
v
a=a a x + y
tt



v
r
2
cc
v
a=a=
r
v
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Uniform Circular Motion

UCM

, a special case of 2-D motion where:

-^

The radius of motion (r) is constant

-^

The speed (v) is constant

-^

The velocity changes as object continually changesdirection

-^

Since

is changing (v is not but direction is), the object

must be accelerated:

-^

The direction of the acceleration vector is always toward thecenter of the circular motion and is referred to as thecentripetal acceleration

-^

The magnitude of centripetal acceleration:

ˆ^

x

c^

x^

y

v

v

a =a

a^

x +

y

t^

t 

^

^

^

^

^

v

r

2

c^

c

v

a =a =

r

 v

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Derivation of Centrifugal Acceleration

Consider an object in uniform circular motion, where:

r = constant {radius of travel}v = constant {speed of object} The magnitude of the centripetal acceleration can be

obtained by comparing the similar triangles for positionand velocity:

x v r y

 x

y

The direction of position and velocity vectors both shift by thesame angle, resulting in the following relation:

2 c

r^

v^

v^

r^

v^

v^

r

=

v=

=

v a =

r^

v^

r^

r^

t^

r

t

^

^

^

^



 ^

^



r^1

r^2

r  Position only

v vv

 Velocity only

r 2 v time, t

2

time, t v1^ r^1

1

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Centripetal Force & Gravitation

Assume the Earth travels about the Sun in UCM:Questions:

1.^

What force is responsible for maintain the Earth’s circular orbit?

2.^

Draw a Free-Body Diagram for the Earth in orbit.

3.^

Calculate gravitational force exerted on the Earth due to the Sun.

4.^

What is the centripetal acceleration of the Earth?

5.^

What is the Earth’s tangential velocity in its orbit around the Sun?

Sun

Earth

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Centripetal Force vs. Centrifugal Force

•^

An object moving in uniform circular motion experiences anoutward “force” called centrifugal force (due to the object’sinertia)

-^

However, to refer to this as a force is technically incorrect.More accurately, centrifugal force _______.– is a consequence of the observer located in an accelerated (revolving)

reference frame and is therefore a fictitious force (i.e. it is not really aforce it is only perceived as one)

  • is the perceived response of the object’s inertia resisting the circular

motion

(& its rotating environment)

  • has a magnitude equal to the centripetal force acting on the body

Centripetal force & centrifugal force are

NOT action-reaction pairs…

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Banked Curves

-^

Engineers design banked curves to increasethe speed certain corners can be navigated

-^

Banking corners decreases the dependenceof static friction (between tires & road)necessary for turning the vehicle into acorner.

-^

Banked corners can improve safetyparticularly in inclement weather (icy or wetroads) where static friction can becompromised

-^

How does banking work?

-^

The normal force (F

) of the bank on the carN

assists it around the corner!

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Vertical Circular Motion

•^

Consider the forces acting on a motorcycle performing aloop-to-loop: • Can you think of other objects that undergo similarmotions?

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