



Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Community
Ask the community for help and clear up your study doubts
Discover the best universities in your country according to Docsity users
Free resources
Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors
The concepts of set operations, including the complement, intersection, and union of sets. It provides examples and step-by-step solutions for finding the complement, intersection, and union of different sets. It also includes exercises for practicing these concepts.
Typology: Schemes and Mind Maps
1 / 6
This page cannot be seen from the preview
Don't miss anything!
Section 1.4 Operations with sets – Union, Intersection and Complement
A universal set for a particular problem is a set which contains all the elements of all the sets in the problem.
used.
In this section we will create subsets of a given universal set and use set operations to create new subsets of the universal set.
There are three set operations we will learn in this section.
Complement: The complement of a set A is symbolized by A’ and it is the set of all elements in the universal set that are not in A.
Intersection: The intersection of sets A and B is symbolized by 𝐴 ∩ 𝐵 and is the set containing all of the elements that are common to both set A and set B.
Union: The union of set A and B is symbolized 𝐴 ∪ 𝐵 and is the set containing all the elements that are elements of set A or of set B or that are in both Sets A and B.
Here is a quick example to illustrate the 3 definitions.
Example: Let U be a universal set and A and B be subsets of U defined as follows.
U = {1,2,3,4,5} A = {1,2,3} B = {2,3,4}
Find A’
A’ is all of the elements in the Universal set that are not in set A.
Answer: A’ = {4,5}
Find 𝑨 ∩ 𝑩 (This is asking me to find all of the elements that A and B have in common.)
Answer: 𝐴 ∩ 𝐵 = {2,3}
Find 𝑨 ∪ 𝑩 (This is asking me to list all of the elements in A followed by all of the elements in B, then delete any elements that are written twice.)
𝐴 ∪ 𝐵 = {1,2,3,2,3,4}
Answer: 𝐴 ∪ 𝐵 = {1,2,3,4}
Example: Let U be a universal set and A and B be subsets of U defined as follows.
U = {a,b,c,d,e,f} A = {a,b,c} B = {c,d,e}
Find 𝑨′ ∩ 𝑩
First I need to find A’, which is all of the elements in U that aren’t in set A.
A’ = {d,e,f}
Now I can intersect the two sets.
𝐴′^ ∩ 𝐵 = {d,e,f} ∩ {c,d,e} (now find what the two sets have in common)
Answer: {d,e}
Find 𝑨 ∪ 𝑩′
First I need to find B’
B’ = {a,b,f}
A ∪ B′ = {a,b,c} ∪ {a,b,f} (put all 6 elements in a big set then delete the duplicates)
= {a,b,c,a,b,f}
Answer: {a,b,c,f}
#1-10: Find the following sets.
U = {a,b,c,d,e} A = {c,d,e} B = {a,c,d}
A’ 2) B’
𝐴 ∪ 𝐵 4) 𝐴′ ∪ 𝐵′
𝐴 ∩ 𝐵 6) 𝐴′ ∩ 𝐵′
𝐴′ ∩ 𝐵 8) 𝐴 ∩ 𝐵′
𝐴′ ∪ 𝐵 10) 𝐴 ∪ 𝐵′
Find (𝑩 ∪ 𝑪)′
I have to work on the inside of the parenthesis first.
So I will first find: 𝐵 ∪ 𝐶
𝐵 ∪ 𝐶 = {c,d,e} ∪ {d,e,f}
𝐵 ∪ 𝐶 = {c,d,e,d,e,f}
𝐵 ∪ 𝐶 ={c,d,e,f}
Now I can do the complement.
I can replace the inside of the parenthesis with {c,d,e,f} and proceed to find its complement.
(B ∪ C)′ = (c,d,e,f)’ (my answer will be all the elements of set U that are not in this set.)
Answer: {a,b}
Find 𝑨 ∪ (𝑩 ∪ 𝑪)′
First I need to simplify the parenthesis (B ∪ C)′ I just figured out that (B ∪ C)′ = {a,b}, so I will use the work I have already done
A ∪ (B ∪ C)′
= A ∪ {a, b}
= {a,b,c} ∪ {a,b}
= {a,b,c,a,b}
Answer: {a,b,c}
Find 𝐴′ ∩ (𝐵 ∩ 𝐶′)
I need to simplify the inside of the parenthesis first.
(𝐵 ∩ 𝐶′)
= {c,d,e} ∩ {a,b,c}
= {c}
𝐴′ ∩ (𝐵 ∩ 𝐶′)
= A’ ∩ {𝑐}
= {d,e,f} ∩ {c}
Answer: ∅ (empty set)
#21-32: Find the following sets.
U = {1,2,3,4,5,6} A = {1,2,3} B = {2,3,4} C = {1,5}
𝐴 ∩ 𝐶 22) 𝐵 ∩ 𝐶
𝐴 ∪ 𝐶 24) 𝐵 ∪ 𝐶
𝐴 ∩ 𝐵 ∪ 𝐶 26) 𝐴 ∪ 𝐵 ∩ 𝐶
𝐵 ∪ 𝐶 ∩ 𝐴 28) 𝐵 ∩ 𝐴 ∪ 𝐶
𝐴′ ∩ 𝐵 30) 𝐴 ∩ 𝐵′
𝐴′ ∪ 𝐵 ∩ 𝐶′ 32) 𝐵′ ∩ 𝐴 ∪ 𝐶′
#33-44: Find the following sets.
U = {a,b,c,d} A = {a,b,c} B = {b,c,d} C = {a,d}
𝐴 ∩ 𝐶′ 34) 𝐵′ ∩ 𝐶
𝐴′ ∪ 𝐶′ 36) 𝐵′ ∪ 𝐶′
𝐴′ ∩ 𝐵 ∪ 𝐶′ 38) 𝐴′ ∪ 𝐵′ ∩ 𝐶
𝐵′ ∪ 𝐶′ ∩ 𝐴 40) 𝐵′ ∩ 𝐴′ ∪ 𝐶
𝐴′ ∩ 𝐵′ 42) 𝐴 ∩ 𝐵′
𝐴′ ∪ 𝐵′ ∩ 𝐶′ 44) 𝐵 ∩ 𝐴′ ∪ 𝐶′