Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Unit Conversions | Montgomery College, Schemes and Mind Maps of Dimensional Analysis

cm3 in3. 1 mL = 1 cm3, 1 mL = 10−3 L. 1 in. = 2.54 cm. L. mL g kg ... 1 cm3 = 10-6 m3 = 0.000 001 m3 ... g/cm3. Convert the density to units of kg/m3.

Typology: Schemes and Mind Maps

2021/2022

Uploaded on 09/12/2022

pierc
pierc 🇺🇸

4.3

(4)

220 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Unit Conversions
Important Tips
Always write every number with its associated unit.
Always include units in your calculation.
you can do the same kind of operations on units as you can on numbers
using units as a guide to problem solving is called dimensional analysis
Conversion factors are relationships between two units
Conversion factors can be generated from equivalence statements (e.g. 1 inch = 2.54 cm)
Arrange conversion factors so the starting unit is on the bottom of the first conversion factor
Conceptual Plan
given unit × related unit
given unit = desired unit given unit ×related unit
given unit ×desired unit
related unit = desired unit
Systematic Approach to Problem Solving
Convert 5.70 L to cubic inches
Sort Information Given:
Desired:
5.70
in.3
Strategize Conceptual
Plan
Relationships:
Follow the conceptual plan
to solve the problem Solution: 5.70 L × 1mL
10‐3 L × 1cm3
1mL × 󰇛1in.󰇜3
󰇛2.54cm󰇜3 = 347.835 in.3
Sig. figs. and round Round 347.835 in.3 = 348 in.3 (3 sig. fig.)
Check units are correct; number makes sense: in.3 << L
Density as a Conversion Factor
What is the mass in kg of 173,231 L of jet fuel whose density is 0.768 g/mL?
Sort Information Given:
Desired:
173.231L, density = 0.768 g/mL
Mass, kg
Strategize Conceptual
Plan
Relationships:
Follow the conceptual plan
to solve the problem Solution: 173,231L × 1mL
10‐3 L × 0.768g
1mL ×1kg
1000g =1.3304 x105 kg
Sig. figs. and round Round 1.3304 x 105 kg = 1.33 x 105 kg
Check units and number makes sense
1 mL = 0.768 g (from density)
1 mL = 103 L, 1 kg = 1000g
Density (g/cm3, g/mL)
conversion factor
Mass Volume
LmL cm3 in3
1 mL = 1 cm3, 1 mL = 103 L
1 in. = 2.
5
4
c
m.
LmL g k
g
pf2

Partial preview of the text

Download Unit Conversions | Montgomery College and more Schemes and Mind Maps Dimensional Analysis in PDF only on Docsity!

Unit Conversions

Important Tips

 Always write every number with its associated unit.  Always include units in your calculation.  you can do the same kind of operations on units as you can on numbers  using units as a guide to problem solving is called dimensional analysis  Conversion factors are relationships between two units  Conversion factors can be generated from equivalence statements (e.g. 1 inch = 2.54 cm)  Arrange conversion factors so the starting unit is on the bottom of the first conversion factor

Conceptual Plan

given unit ×

related unit

given unit = desired unit^ given unit^ ×^

related unit

given unit ×^

desired unit

related unit = desired unit

Systematic Approach to Problem Solving

Convert 5.70 L to cubic inches  Sort Information Given: Desired:

in. 3  Strategize Conceptual Plan Relationships:

 Follow the conceptual plan

to solve the problem Solution:^ 5.70 L^ ×^

1 mL

10 ‐3^ L ×^

1 cm^3

1 mL ×^

ሺ1 in.ሻ 3

ሺ2.54 cmሻ 3 = 347.835 in.^

3

 Sig. figs. and round Round^ 347.835 in.^3 = 348 in.^3 (3 sig. fig.)

 Check units are correct; number makes sense: in.^3 << L

Density as a Conversion Factor

What is the mass in kg of 173,231 L of jet fuel whose density is 0.768 g/mL?  Sort Information Given: Desired:

173.231L, density = 0.768 g/mL Mass, kg  Strategize Conceptual Plan Relationships:

 Follow the conceptual plan

to solve the problem Solution:^ 173,231L^ ×^

1 mL

10 ‐3^ L ×^

0.768 g

1 mL ×^

1 kg

1000g =1.3304 x^

(^5) kg

 Sig. figs. and round Round^ 1.3304 x 10^5 kg = 1.33 x 10^5 kg

 Check units and number makes sense

1 mL = 0.768 g (from density) 1 mL = 10−^3 L, 1 kg = 1000g

Density (g/cm3, g/mL)

conversion factor Mass Volume

L mL cm^3 in 3 1 mL = 1 cm 3 , 1 mL = 10−^3 L 1 in. = 2.54 cm.

L mL g (^) kg

Volume ( 1 mL = 1 cm^3 ) solid volume (cubic centimeters, cm^3 ) liquid or gas volume (milliliters, mL) 1 m^3 = 10 6 cm^3 1 cm^3 = 10 -6^ m^3 = 0.000 001 m^3

1 mL = 0.001 L = 10 -3^ L 1L = 1 dm^3 = 1000 mL =10 3 mL

Practice Problems

  1. Use the prefix multipliers to express each measurement without any exponents. a) 1.2 × 10 -9^ m b) 22 × 10 -15^ s c) 1.5 × 10 9 g d) 3.5 × 10 6 L
  2. Perform the following conversions. a) 25.5 mg to g b) 4.0 × 10 -10^ m to nm c) 0. 575 mm to μm d) 68.3 cm^3 to cubic meters e) 242 lb to milligrams (1lb = 453.6 g)
  3. The density of platinum is 21.45 g/cm 3 at 20 °C. What is the volume of 87.50 g of this metal at this temperature?
  4. Mercury is the only metal that is a liquid at room temperature. Its density is 13.6 g/mL. How many grams of mercury will occupy a volume of 95.8 mL?
  5. Liquid nitrogen is obtained from liquefied air and is used to prepare frozen goods and in low- temperature research. The density of the liquid at its boiling point (-196 °C) is 0.808 g/cm^3. Convert the density to units of kg/m^3.

References: Tro, Chemistry: A Molecular Approach 2 nd^ ed., Pearson Brown/LeMay/Bursten, Chemistry: The Central Science, 12 th^ ed., Pearson

SI Prefix Multipliers

Prefix Symbol Multiplier Power of 10

giga G 1,000,000,000^ Base x 10^9

mega M 1,000,000 Base x 10 6

kilo k 1,000 Base x 10^3

deci d 0.1 Base x 10 -

centi c 0.01 Base x 10-

milli m 0.001^ Base x 10^ -

micro μ 0.0000001 Base x 10 -

mano n 0.0000000001 Base x 10 -

pico p 0.0000000000001 Base x 10 -

Answers

. a)1.2 nm; b) 22 fs; c) 1.5 Gg; d) 3.5 ML 1

mg 8 e) 1.10 x 10 3 m -5 g; b) 0.40 nm; c) 575 μm d) 6.83 x 10 -2. a) 2.55 x 10 2 3. 808 kg/m^5^ g 3. 1.30 x 10^4 3. 50.35 cm^3