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A step-by-step guide on how to solve triangles using various trigonometry formulas such as law of sines, law of cosines, and heron's formula. It covers different scenarios like asa, aas, ssa, sas, and sss, and also explains how to find the area of a triangle.
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“Solving a triangle” means finding the sizes of all angles and sides. To get the most accurate results, use given information whenever possible and do not approximate until the final step.
I. Given two angles and one side (ASA or AAS)
A. Find third angle by subtracting sum of known angles from 180 o. B. Use Law of Sines to find unknown sides.
II. Given two sides and an angle opposite one of the known sides (SSA)
A. Use Law of Sines to find angle opposite other known side. (If the sine of the angle is greater than one , then NO triangle can be constructed with given parts.) B. Subtract the angle found in Part A from 180 o to get second possibility. One of the angles found in Parts A and B will be obtuse. Add obtuse angle to given angle.
III. Given two sides and included angle (SAS)
A. Use Law of Cosines to find third side. B. Use Law of Sines (or Law of Cosines ) to find smaller of two unknown angles. This angle will be opposite the shorter side. This angle will always be acute, thus avoiding ambiguity. C. Subtract sum of the two angles from 180 o to find third angle.
IV. Given three sides (SSS)
A. Use Law of Cosines to find largest angle (opposite largest side). Finding this angle first guarantees that remaining two angles will be acute; no ambiguity exists. B. Use Law of Sines (or Law of Cosines ) to find a second angle. C. Subtract sum of the two angles from 180 o to find third angle.
V. Given three angles (AAA) - not enough information to determine a unique triangle.
α (^) β
γ
I. Given one side and altitude drawn to that side. (In a right triangle, the legs constitute a a base and corresponding altitude.) A = one-half product of base and altitude II. Given two sides and included angle (SAS) A = one-half product of two sides and sine of angle between them III. Given three sides (SSS) Use Heron’s formula (also called Hero’s formula)
IV. C
b a ∆ABC is probably not a right triangle, however all of these formulas will work with a right triangle.
A c B
LAW OF SINES
I. sin^ sin^ sin a b c
α (^) = β (^) = γ a b c sin α sin β sin γ
II. Use the two ratios which best match the given information. III. There is an ambiguity involved when using the Law of Sines to find an angle. See Part II under “Solving a Triangle”.
LAW OF COSINES
I. a^2 = b^2 + c 2 − 2bc(cos α ); b^2 = a 2 + c 2 − 2ac(cos β ); c 2 = a 2 + b^2 −2ab(cos γ )
II. ; ; b 2 c 2 a^2 cos 2bc
α = +^ − a 2 c 2 b^2 cos 2ac
β = +^ − a 2 b 2 c^2 cos 2ab
γ = +^ −
III. There is no ambiguity involved when using Law of Cosines to find an angle. The angle found will be unique.
AREA OF A TRIANGLE
I. A 1 bh 2
II. A 1 bc(sin ); ; 2
= α A 1 ac(sin ) 2
= β A 1 ab(sin ) 2
= γ
III. Heron’s formula:
A s(s a)(s b)(s c), where s perimeter 2