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Work in Thermodynamic Processes - General Physics I - Lecture Slides, Slides of Physics

Following points are the summary of these Lecture Slides : Work in thermodynamic Processes, State, Description, Pressure, Volume, Temperature, internal Energy, Macroscopic State, internal thermal, Isolated System

Typology: Slides

2012/2013

Uploaded on 07/26/2013

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Work in Thermodynamic Processes
State Variables
State of a system
Description of the system in terms of state variables
Pressure
Volume
Temperature
Internal Energy
A macroscopic state of an isolated system can be specified only if the
system is in internal thermal equilibrium
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Download Work in Thermodynamic Processes - General Physics I - Lecture Slides and more Slides Physics in PDF only on Docsity!

Work in Thermodynamic Processes –

State Variables

  • State of a system
    • Description of the system in terms of state variables
      • Pressure
      • Volume
      • Temperature
      • Internal Energy
    • A macroscopic state of an isolated system can be specified only if the system is in internal thermal equilibrium

Work

  • Work is an important energy transfer

mechanism in thermodynamic

systems

  • Heat is another energy transfer

mechanism

  • Example: gas cylinder with piston
    • The gas is contained in a cylinder with a moveable piston
    • The gas occupies a volume V and exerts pressure P on the walls of the cylinder and on the piston

Work on a Gas Cylinder

  • When the gas is compressed
    • ΔV is negative
    • The work done on the gas is positive
  • When the gas is allowed to expand
    • ΔV is positive
    • The work done on the gas is negative
  • When the volume remains constant
    • No work is done on the gas

W = - P ΔV

Notes about the Work Equation

  • If the pressure remains

constant during the

expansion or compression,

the process is called an

isobaric process

  • If the pressure changes, the

average pressure may be

used to estimate the work

done

W = - P ΔV

Work done on the gas Work=Area under the curve

W = - P ΔV

PV Diagrams

  • The curve on the diagram is called the path taken between

the initial and final states

  • The work done depends on the particular path
    • Same initial and final states, but different amounts of work are done

Question

Find work done by the gas in this cycle. P 2 P 1 V 1 V 2

Other Processes

  • Isovolumetric
    • Volume stays constant
    • Vertical line on the PV diagram
  • Isothermal
    • Temperature stays the same
  • Adiabatic
    • No heat is exchanged with the surroundings

W = nRT ln

Vf

V

i

& =^ PiVi ln^

Vf

V

i

Example:

Given: n = 1 mole Ti = 96.2 K Tf = 144.3 K Vi = 0.2 m^3 Vf = 0.3 m^3 P = const Find: W=? ( ) ( ) J W P V PVf Vi m 400 4000 Pa 0.3m 0. 2 3 3 = = Δ = − = −

  1. Isobaric expansion: Calculate work done by expanding gas of 1 mole if initial pressure is 4000 Pa, initial volume is 0.2 m 3 , and initial temperature is 96.2 K. Assume a two processes: (1) isobaric expansion to 0.3 m 3 , Tf=144. K (2) isothermal expansion to 0.3 m 3 . Also:
  2. 5
  3. 2
  4. 3 3 3 = = = = m m V V nR P V nR P V T T i f i i f f i f A 50% increase in temperature!

Processes for Transferring Energy

• By doing work

  • Requires a macroscopic displacement of the point of

application of a force

• By heat

  • Occurs by random molecular collisions

• Results of both

  • Change in internal energy of the system
  • Generally accompanied by measurable macroscopic

variables

  • Pressure
  • Temperature
  • Volume How can energy be transferred?

First Law of Thermodynamics

• Consider energy conservation in thermal

processes. Must include:

  • Q
    • Heat
    • Positive if energy is transferred to the system
  • W
    • Work
    • Positive if done on the system
  • U
    • Internal energy
    • Positive if the temperature increases

Applications of the First Law:

1. Isolated System

  • An isolated system does not interact with its

surroundings

  • No energy transfer takes place and no work is done
  • Therefore, the internal energy of the isolated system

remains constant

Example:

Given: n = 1 mole Vi = 0.2 m^3 Vf = 0.3 m^3 P = const Q=500 J Find: Δ U=? ( ) ( ) J W P V PVf Vi m 400 4000 Pa 0.3m 0. 2 3 3 = = Δ = − = −

  1. Isobaric expansion: If 500 J of heat added to ideal gas that is expanding from 0. m 3 to 0.3 m 3 at a constant pressure of 4000 Pa, what is the change in its internal energy? Use 1 st law of thermodynamics: U Q W J J J
Q U W

Example: Cyclic Process in a PV Diagram

  • This is an ideal monatomic gas confined in a cylinder by a moveable piston
  • A to B is an isovolumetric process which increases the pressure
  • B to C is an isothermal expansion and lowers the pressure
  • C to A is an isobaric compression
  • The gas returns to its original state at point A

Applications of the First Law:

3. Isothermal Processes

  • Isothermal means constant

temperature

  • The cylinder and gas are in

thermal contact with a large

source of energy

  • Allow the energy to transfer into

the gas (by heat)

  • The gas expands and pressure

falls to maintain a constant

temperature (ΔU = 0 )

  • The work done is the negative

of the heat added

ln. f i ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ = V V W nRT