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Worksheet Introduction to the Mole Ratio and Stoichiometry with Answers, Exercises of Chemistry

2 assignments on stoichiometry and mole ratios problems, check your work with answer key.

Typology: Exercises

2020/2021

Uploaded on 04/20/2021

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If you are a student that HAS access to technology, this is not the packet for you. This
packet is for students who pick up and drop off their work at the front office every week.
If you have access to technology, please go back to your teacher’s website and complete
the correct assignment.
!
!
Name:!_____________________________________________!Period:!____________!Teacher:!____________________________!
!
Distance!Learning!Week!7!Paper!Packet!
5/18/2020!–!5/24/2020!
Assignment 7.1 - INTRODUCTION TO THE MOLE RATIO & STOICHIOMETRY
Patriot Pack Cookie Recipe:
3 cups dough + 1 cup chocolate chips 15 cookies
Additional Information for the recipe:
1 cup of dough weighs 200.00 grams
1 cup chocolate chips has 100. chips in it.
Use the recipe and the additional information to answer the questions below.
1. How many cookies can you make from 6.00 cups dough, assuming an excess of chips (that means you have
as many chips as you need to make the cookies)?
2. How many cookies can you make from 4.00 cups of chips, assuming excess of dough?
3. How many cookies can you make from 17.5 cups of dough, assuming an excess of chips?
4. How many cookies can you make from 18.0 cups of dough and 6.00 cups of chips?
5. How many cookies can you make from 18.0 cups of dough and 2.00 cups of chips?
6. How many cookies can you make from 400 chocolate chips, assuming enough dough?
7. How many cookies can you make from 400. g of dough, assuming enough chips?
8. How many cups of cookie dough are needed to make 60. Cookies?
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Download Worksheet Introduction to the Mole Ratio and Stoichiometry with Answers and more Exercises Chemistry in PDF only on Docsity!

If you are a student that HAS access to technology, this is not the packet for you. This packet is for students who pick up and drop off their work at the front office every week. If you have access to technology, please go back to your teacher’s website and complete the correct assignment. Name: _____________________________________________ Period: ____________ Teacher: ____________________________ Distance Learning Week 7 Paper Packet 5/18/2020 – 5/24/

Assignment 7.1 - INTRODUCTION TO THE MOLE RATIO & STOICHIOMETRY

Patriot Pack Cookie Recipe:

  • 3 cups dough + 1 cup chocolate chips → 15 cookies Additional Information for the recipe:
  • 1 cup of dough weighs 200.00 grams
  • 1 cup chocolate chips has 100. chips in it. Use the recipe and the additional information to answer the questions below.
  1. How many cookies can you make from 6.00 cups dough, assuming an excess of chips ( that means you have as many chips as you need to make the cookies )?
  2. How many cookies can you make from 4.00 cups of chips, assuming excess of dough?
  3. How many cookies can you make from 17.5 cups of dough, assuming an excess of chips?
  4. How many cookies can you make from 18.0 cups of dough and 6.00 cups of chips?
  5. How many cookies can you make from 18.0 cups of dough and 2.00 cups of chips?
  6. How many cookies can you make from 400 chocolate chips, assuming enough dough?
  7. How many cookies can you make from 400. g of dough, assuming enough chips?
  8. How many cups of cookie dough are needed to make 60. Cookies?

An educated guess… What do you think stoichiometry is? I think stoichiometry is ____________________________________________________________________ because ______________________________________________________________________________________.

Assignment 7.2: Mole Ratio Notes

How to interpret a balanced chemical equation

You can interpret a balanced chemical equation in 2 ways:

  1. In terms of atoms or molecules
  2. In terms of moles A bit of review:
  • A molecule consists of at least 2 or more atoms bonded together:
  • Example: As you can see, a molecule usually consists of coefficients and subscripts. The coefficients can be interpreted as molecules or moles. While the subscripts can be interpreted as atoms or moles. To interpret the chemical formula in terms of molecules, we will say 1 molecule of CO 2 consists of 1 atom of carbon (C) and 2 atoms of oxygen (O). Here is a picture of the interpretation: To interpret the chemical formula in terms of moles, we will say 1 mol of CO 2 consists of 1 mol of carbon (C) and 2 mol of oxygen (O). Here is a picture of the interpretation: Now, let’s apply our understanding to interpret the following equation in terms of molecules and moles. When hydrogen (H 2 ) reacts with iodine (I 2 ) to produce hydrogen iodide (HI), we can write a balanced chemical equation for the reaction as: H 2 + I 2 – > 2HI. To interpret this equation in terms of molecules: we can say that 1 molecule of H 2 reacts with 1 molecule of I 2 to give 2 molecules of HI. Recall that the number 1 is implied when you don’t see a number written in front of a chemical symbol or formula in a chemical equation. To interpret equation A in terms of moles: we can say that 1 mole of H 2 molecules reacts with 1 mole of I 2 molecules to give 2 moles of HI molecules.

Problem : 4 Al + 3 O 2 à 2 Al 2 O 3 If I have 6 moles of Al, how many moles of O 2 will react with it? Solved: To solve the problem:

  1. Find the given and the want. Given = 6 mol Al Want =? mol O 2
  2. Find the mole ratio between given and want. 4 moles Al: 3 moles O 2
  3. Use dimensional analysis to cover the given to the want. Use the mole ratio as the conversion factor, and remember to put the units you START with on the BOTTOM so they cancel out!
  4. To calculate, multiply the top numbers and divide by the bottom numbers. (6 x 3 ÷ 4 = 4.5) 6 𝑚𝑜𝑙 𝐴𝑙 ×

Now try these Problems : (answers at end of packet)

  1. 2 Mg + O 2 à 2 MgO
  • If I have 3.6 moles of O 2 , how many moles of MgO can I make?
  1. 2 Mg + O 2 à 2 MgO
  • If I want to make 4.6 moles of MgO, how many moles of Mg do I need?
  1. C 3 H 8 + 5 O 2 à 3 CO 2 + 4 H 2 O
  • If 4.5 moles of C 3 H 8 combusts, how many moles of CO 2 will be produced?
  1. C 3 H 8 + 5 O 2 à 3 CO 2 + 4 H 2 O
  • If I want to produce 7.65 moles of H 2 O, how much O 2 should I use? Assignment 7.3: Mole Ratio Practice Before you begin, make sure you have completed assignment 7.1 and 7.2. Please show your work for questions 1-14 on a separate sheet of paper. Take a picture of your work and submit it to turnitin.com. You must show your work in order to receive full credit.
  1. Consider the following equation: N 2 (g) + 3H 2 (g) → 2NH 3 (g) a. The mole ratio for N 2 : H 2 is 1 mol of N 2 : 3 moles of H 2 b. The mole ratio for N 2 : NH 3 is _____ c. The mole ratio for H 2 : NH 3 is 3 mol of H 2 : 2 mol of NH 3 d. The mole ratio for N 2 : H 2 : NH 3 is _____

Questions 3-12: Use the following chemical equation, it’s already balanced.

2Na + Cl 2 → 2NaCl

  1. What is the mole ratio of Na : Cl 2 : NaCl?
  2. What is the mole ratio of Na : Cl 2?
  3. What is the mole ratio of Na : NaCl?
  4. What is the mole ratio of Cl 2 : NaCl? Example: If the reaction consumes 3 moles of Na (start), how many moles of Cl 2 (end) will be consumed? Na : Cl 2 mole ratio = 2 mol of Na : 1 mole of Cl 2 (from question 3 mol of Na ( what you start with ) 1 mol of Cl 2 = 1. 5 mol of Cl 2 ( what you end with ) 2 mol of Na Your mole ratio will go in the middle. Notice that the mol of Na goes on the bottom because it needs to cancel out the mol of Na in the top left. Now multiply everything on the top together, divided by everything on the bottom → (3 x 1 mol of Cl 2 ) / (2) = 1.5 mol of Cl 2

2Na + Cl 2 → 2NaCl

  1. If the reaction consumes 7.5 moles of Na, how many moles of Cl 2 will be consumed? Na : Cl 2 mole ratio = _______________ (answer to question 4) ( what you start with ) ( what you end with ) remember that your mole ratio goes in the middle
  2. If the reaction consumes 4 moles of Cl 2 , how many moles of Na will be consumed?
  3. If the reaction produces 13.5 moles of NaCl, how many moles of Cl 2 will be consumed? NaCl : Cl 2 mole ratio = _______________ (answer to question 5)

Answer Keys: 7.

  1. 30 cookies
  2. 60 cookies
  3. 87 cookies
  4. 90 cookies
  5. 30 cookies (you’re limited by how many chips you have, you have enough dough for 90 cookies, but not enough chips and cookies without chocolate chips are basically crackers).
  6. 60 cookies
  7. 10 cookies
  8. 12 cups dough 7.
  1. 7.6 mol MgO
  2. 4.6 mol Mg
  3. 13.5 mol CO 2
  4. 9.56 mol O 2
  1. 3.75 mol Cl 2 7 ) 8 mol Na
  2. 6.75 mol Cl 2 9 ) 23 mol NaCl
  3. 8.85 mol O 2 11 ) 1.47 mol Fe 2 O 3
  4. 10.25 mol H 2 O
  5. 0.04 mol C 3 H 8
  6. 0.312 mol CO 2 challenge problem: 46.2 mol H 2 O; 831.6 g H 2 O