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Worksheet: Practice on Set Theory, Exercises of Mathematics

Set theory worksheet in given the different questions about sets.

Typology: Exercises

2021/2022

Uploaded on 03/31/2022

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WORKSHEET 1: PRACTICE ON SET THEORY
MATH 2106-D
(1) Let X={1,5,8}and Y={1, a, b}. Write down the following sets:
(a) XY.
(b) XY.
(c) P(XY).
(d) X×Y
(2) If Iis a set, called an index set, and for each α I, we have a set Aα, then we
can consider the union and intersection
α∈I Aα={x|xAαfor at least one Aαwith α I} ,
α∈I Aα={x|xAαfor every Aαwith α I} .
Determine what the following sets are, and explain your answer.
(a) nN1
n,1
n
(b) nN1
n,1
n
(c) aR{(x, y, z)|x2+y2=a2, z =a}
(3) Explain why |AB|=|A|+|B| |AB|. Can you find a similar formula for
|ABC|in terms of cardinalities of A, B, C and intersections between these
sets?
(***) Let Xbe the set of all sets that are not elements of themselves, that is,
X={A|Ais a set, A 6∈ A}.
Explain why the existence of this “set” doesn’t make logical sense. (Hint: Is
XX?) This conundrum, known as Russell’s Paradox, shows that in order
to be 100% rigorous with set theory, one must be very careful when describing
which sets are “allowed”; the standard resolution to this problem is to base set
theory on a precise set of axioms, such as ZFC.
1
pf2

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WORKSHEET 1: PRACTICE ON SET THEORY

MATH 2106-D

(1) Let X = { 1 , 5 , 8 } and Y = { 1 , a, b}. Write down the following sets: (a) X ∩ Y. (b) X ∪ Y. (c) P(X ∩ Y ). (d) X × Y

(2) If I is a set, called an index set, and for each α ∈ I, we have a set Aα, then we can consider the union and intersection ∪α∈I Aα = {x|x ∈ Aα for at least one Aα with α ∈ I} , ∩α∈I Aα = {x|x ∈ Aα for every Aα with α ∈ I}. Determine what the following sets are, and explain your answer. (a) ∩n∈N

− (^1) n , (^) n^1

(b) ∪n∈N

− (^1) n , (^) n^1

(c) ∪a∈R{(x, y, z)|x^2 + y^2 = a^2 , z = a}

(3) Explain why |A ∪ B| = |A| + |B| − |A ∩ B|. Can you find a similar formula for |A ∪ B ∪ C| in terms of cardinalities of A, B, C and intersections between these sets?

(***) Let X be the set of all sets that are not elements of themselves, that is,

X = {A|A is a set, A 6 ∈ A}. Explain why the existence of this “set” doesn’t make logical sense. (Hint: Is X ∈ X?) This conundrum, known as Russell’s Paradox, shows that in order to be 100% rigorous with set theory, one must be very careful when describing which sets are “allowed”; the standard resolution to this problem is to base set theory on a precise set of axioms, such as ZFC. 1

2 MATH 2106-D

Handy notation cheat sheet:

  • a ∈ A, read “a is in A,” means that a is an element of A
  • A ⊆ B, read “A is a subset of B,” means that every element of A is also an element of B
  • A = B, read “A equals B,” if A and B have the same elements
  • |A| is the cardinality, or size of A, namely the number of its elements (if A is finite; if A is infinite, one often writes |A| = ∞ as a shorthand, although this isn’t very precise)
  • ∅ denotes the empty set, which is the only set with no elements
  • N = { 1 , 2 , 3 ,... } is the set of natural numbers
  • Z = {... , − 3 , − 2 , − 3 , 0 , 1 , 2 , 3 ,... } is the set of integers (whole numbers)
  • Q = {ab | a, b ∈ Z, and b 6 = 0} is the set of rational numbers (fractions)
  • R is the set of real numbers
  • A×B denotes the Cartesian product A×B = {(a, b) | a ∈ A , b ∈ B} consisting of ordered pairs of elements from A and B. The n-fold Cartesian product A ×... × A is denoted by An.
  • The notations P(A) and 2A^ both denote the power set of A, namely the set of all subsets of A. That is, P(A) = {X | X ⊆ A}.
  • The union of A and B is A ∪ B = {x|x ∈ A or x ∈ B} (where or in math always means that one or the other or both conditions hold)
  • The intersection of A and B is A ∩ B = {x|x ∈ A and x ∈ B}
  • The set difference of A and B is A \ B = A − B = {x|x ∈ A and x 6 ∈ B}
  • If U is the universal set, then the complement of A is Ac^ = A = U \ A (i.e., the set of everything not inside of A, in whatever universal set you have given by the context)