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Calculation of Centripetal Force and Tension in a Hanging Mass, Exercícios de Engenharia Elétrica

The calculations for the centripetal force and tension in a mass hanging from a balance at the equator of a spinning earth. It uses newton's second law and the given mass and acceleration to determine the force and tension. The calculations are based on eq. 6-18 and newton's second law.

Tipologia: Exercícios

Antes de 2010

Compartilhado em 08/10/2007

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51. (a) The centripetal force is given by Eq. 6-18:
F=mv2
R=(1)(465)2
6.4×106=0.034 N .
(b) Calling downward (towards the center of Earth) the positive direction, Newton’s second law leads
to
mg T=ma
where mg =9.80 N and ma =0.034 N, calculated in part (a). Thus, the tension in the cord by
which the body hangs from the balance is T=9.80 0.03=9.77 N. Thus, this is the reading for a
standard kilogram mass, of the scale at the equator of the spinning Earth.

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  1. (a) The centripetal force is given by Eq. 6-18:

F =

mv^2 R

(1)(465)^2

6. 4 × 106

= 0.034 N.

(b) Calling downward (towards the center of Earth) the positive direction, Newton’s second law leads to mg − T = ma where mg = 9.80N and ma = 0.034 N, calculated in part (a). Thus, the tension in the cord by which the body hangs from the balance is T = 9. 80 − 0 .0 3 = 9.77 N. Thus, this is the reading for a standard kilogram mass, of the scale at the equator of the spinning Earth.