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Solucionario do Livro (cap4 ) Eletrônica de Potência Daniel Hart, Exercícios de Eletrônica de Potência

Solucionario do Livro (cap4 ) Eletrônica de Potência Daniel Hart

Tipologia: Exercícios

2021

Compartilhado em 13/10/2021

RenanSF
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CHAPTER 4 SOLUTIONS
2/17/10
4-1) Load:
Each diode:
4-2)
4-3)
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19
pf1a
pf1b
pf1c
pf1d
pf1e
pf1f

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CHAPTER 4 SOLUTIONS

2/17/ 4-1) Load: Each diode: 4-2) 4-3)

b) Power is determined from the Fourier series. Using Eq. 4-4 and 4-5. n Vn, V. Zn. Ω In, A. 2 72.0 27.1 2. 4 14.4 47.7 0.

4-8) Load: 4-9) 4-10)

b) Fourier Series n Vn, V. Zn. Ω In, A. 2 72.2 11.7 6. 4 14.4 22.8 0.


4- b) Fourier Series n Vn, V. Zn. Ω In, A. 2 144.3 30.6 4. 4 28.9 60.5 0.

b) Fourier Series n Vn, V. Zn. Ω In, A. 2 72.0 45.5 1. 4 14.4 90.6 0.


4-17) T i m e 1 5 0 m s 1 5 2 m s 1 5 4 m s 1 5 6 m s 1 5 8 m s 1 6 0 m s 1 6 2 m s 1 6 4 m s 1 6 6 m s 1 6 8 m s 1 7 0 m s 1 7 2 m s 1 7 4 m s I ( L 1 ) 0 A 1 0. 0 A 2 0. 0 A 2 6. 5 A 1 0 0 u H 4 0 m H

for the halfwave. The halfwave circuit has fewer diodes, and has only one diode voltage drop rather than two. 4-21)

1  continuous current < 1  Calculated Vo is slightly larger than initial estimate. Try Vo=120 V.:

Therefore, 119 < Vo < 120 V. (Vo=119.6 with more iterations.) c) PSpice results: T i m e 5 5 9 m s 5 6 0 m s 5 6 1 m s 5 6 2 m s 5 6 3 m s 5 6 4 m s 5 6 5 m s 5 6 6 m s 5 6 7 m s 5 6 8 m s 5 6 9 m s 5 7 0 m s V ( O U T + , O U T - ) I ( L 1 ) 0 5 0 1 0 0 1 2 7 R = 7 R = 2 0 R = 2 0 R = 7 R = 7 results in continuous current with Vo = 108 V. R = 20 results in discontinuous current with Vo = 120 V. The simulation was done with C = 10,000 μF. 4-22) PSpice results with a 0.5 Ω resistance in series with the inductance: For Rload = 5 Ω, Vo=56.6 V. (compared to 63.7 volts with an ideal inductor); for Rload = 50 Ω, Vo=82.7 V. (compared to 84.1 volts with an ideal inductor). 4-23)

4-25) a) α = 15° : Check for continuous current. First period: b) α = 75° Check for continuous current. First period:

4-26)a) α = 20°: Check for continuous current. First period: b) α = 80°: Check for continuous current. First period: 4-27) The source current is a square wave of ±Io.

Choose L somewhat larger, say 120 mH, to allow for approximations.